What product(s) forms at the cathode in the electrolysis of an aqueous solution of NaCl?
answer is H2 and OH-. Please explain why!
Electrolysis is a method of separating bonded elements and compounds by passing an electric current through them. An ionic compound NaCl is dissolved with solvent H2O, so that its ions are available in the liquid. An electrical current is applied between a pair of inert electrodes immersed in the liquid. Cathode is a negative charged electrode. Cathode attracts the Na+ from NaCl and H+ ions H2O. Only the H+ are discharged at the cathode because hydrogen has more electron affinity than sodium . Na can lose electrons more easily as compared to H2, but H2 will accept electrons faster at the cathode and gets discharged first. The H+ ions are reduced by electron gain to form hydrogen molecules at the negative electrode which attracts positive ions.
2H+(aq) + 2e– -----> H2(g)
In other words,
2H2O(l) + 2e– -------> H2(g) + 2OH-(aq)
Hence at cathode, water dissociate into H2 and OH-.
What product(s) forms at the cathode in the electrolysis of an aqueous solution of NaCl? answer...
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