Homework Answers
Slope of a straight line can be calculated from the formula Slope= (ΔY) / (ΔX), Where ΔY difference between any two Y co-ordinate value and ΔX is the difference between corresponding X Co-ordinate vale.
In the above data points we can see the difference between any two successive Y ln(P) torr value is 0.68 and corresponding X difference is 0.0001.
Hence from the above formula we can say the slope= - 0.68/0.0001= -6800 K.
The reason for the negative sign is as the value of Y is decreasing with increasing X, it is having a negative slope.
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Clausius-Clapeyron Plot Study the experimental data and graph. 1/T (K-1) In (P (torr)) 0.0031 7.42 0.0032...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AS (in J/mol·K). -30 0.0031 -30.30.003 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -31 -31.5 y = -6861.2x - 9.2495 In (K) -32 -32.5 -33 -33.5 -34 -34.5 -35 1/T in K. Answer:
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures...
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AH° (in kJ/mol). -30 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -30.50.003 -31 y = -6861.2x - 9.2495 -31.5 -32 -32.5 In -33 -33.5 -34 -34.5 -35 1/T in K
Use the class temperature and Kse values to make an Excel graph. y=-4741.7x+18.323 What is the...
Use the class temperature and Kse values to make an Excel graph. y=-4741.7x+18.323 What is the equation for your line? --47417 Slope of the line: (0,18.323) y-intercept of the line: Asoinso: Asorn Hº: Asoin Gºat 0.0°C Asoin Gºat 25.0°C Asoin Gºat 100.0°C On additional paper, clearly show an example of each calculation performed to fill in the report sheet. If calculations are done in your lab notebook, photocopies are acceptable. Include all copies of your Excel graphs. Thermodynamics of the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
Graph should be ln(p) vs 1/T Please show graph and full work for problem Will rate!...
Graph should be ln(p) vs 1/T
Please show graph and full work for problem
Will rate! Please and thank you!
o.18 crm , at 95 %c.1. 3) Data for the vapor pressure of an unknown liquid are given T(C) 84 622, 1.433 694.,542 740 775 398 →5.4 40.4 01 43.4 27.0 30.1 32.8 36.5 484. .182 45.2 550,3 1O 469 The above data can be analyzed by the Clausius-Clapeyron equation According to that equation d (I/T)R where p is the...
An experimental plot of In(k) vs. 1/T is obtained in lab for a reaction. The slope...
An experimental plot of In(k) vs. 1/T is obtained in lab for a reaction. The slope of the best-fit line for the graph is -3880 K. What is the value of the activation energy for the reaction in kJ/mol? The reaction A + 2B + C Products has a rate law of Rate = k[A]][B]. By what factor would the reaction rate change if [B] is tripled? What is the rate for the second order reaction A - Products when...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?]...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
using the pics of data i provided can someone please help find the rate law of...
using the pics of data i provided can someone please help find
the rate law of the reaction and the activatuon energy with
catalyst and without catalyst
Kinetics of the lodine "Clock" Reaction Purpose: Investigate the kinettes reaction of iodide and peoky disulfate, in order to determine the rate law and the Ea with and without a catalyst. deep color Clear builds up because of storch 2 I rag) 5208 cag) → Encaq) + 2 sou? 2- + iaal rate=K[IJh...
ln(k) = -E_a/R 1/T + ln(A) A plot of ln (k)versus 1/T result in a straight...
ln(k) = -E_a/R 1/T + ln(A) A plot of ln (k)versus 1/T result in a straight line with a slope = -E_a/R. The value of E_a can then be calculated using the value of R and to the slope of the line. This experiment uses the Arrhenius equation, which relates the temperature and specific reaction rate constant to determine the activation energy for the crystal violet reaction. The reaction will be performed at different temperatures. Once the order of reaction...
A plot of In P vs. 1/T yields a straight line of slope -2760 K for a substance. What is AHvap of the substance? A....
A plot of In P vs. 1/T yields a straight line of slope -2760 K for a substance. What is AHvap of the substance? A. 37.2 kJ/mol C. 18.7 kJ/mol B. 212 kJ/mol D. 22.9 kJ/mol
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AS (in J/mol·K). -30 0.0031 -30.30.003 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -31 -31.5 y = -6861.2x - 9.2495 In (K) -32 -32.5 -33 -33.5 -34 -34.5 -35 1/T in K. Answer:
A series of experiments were conducted where the equilibrium constant (K) was determined at various temperatures (T). The data was then graphed (shown below). The equation of the line is listed on the graph. Use the graph to determine AH° (in kJ/mol). -30 0.0031 0.0032 0.0033 0.0034 0.0035 0.0036 0.0037 -30.50.003 -31 y = -6861.2x - 9.2495 -31.5 -32 -32.5 In -33 -33.5 -34 -34.5 -35 1/T in K
Use the class temperature and Kse values to make an Excel graph. y=-4741.7x+18.323 What is the equation for your line? --47417 Slope of the line: (0,18.323) y-intercept of the line: Asoinso: Asorn Hº: Asoin Gºat 0.0°C Asoin Gºat 25.0°C Asoin Gºat 100.0°C On additional paper, clearly show an example of each calculation performed to fill in the report sheet. If calculations are done in your lab notebook, photocopies are acceptable. Include all copies of your Excel graphs. Thermodynamics of the...
The rate data of the reaction was collected at different temperatures (°C) and functions of the data plotted to determine the activation energy. 18 17 T 16.5 36.2 47.7 57.3 k 9.86 x 104 2.01 x 106 9.84 x 106 3.41 x 107 16 y = (-1.37 x 10^)x + 58.8 15 14 13 12 = 11 10 0.0030 0.0031 0.0032 0.0033 0.0034 0.0035 1. Clearly label the x and y axes (above) with the proper function. 2. Determine Ea...
Graph should be ln(p) vs 1/T
Please show graph and full work for problem
Will rate! Please and thank you!
o.18 crm , at 95 %c.1. 3) Data for the vapor pressure of an unknown liquid are given T(C) 84 622, 1.433 694.,542 740 775 398 →5.4 40.4 01 43.4 27.0 30.1 32.8 36.5 484. .182 45.2 550,3 1O 469 The above data can be analyzed by the Clausius-Clapeyron equation According to that equation d (I/T)R where p is the...
An experimental plot of In(k) vs. 1/T is obtained in lab for a reaction. The slope of the best-fit line for the graph is -3880 K. What is the value of the activation energy for the reaction in kJ/mol? The reaction A + 2B + C Products has a rate law of Rate = k[A]][B]. By what factor would the reaction rate change if [B] is tripled? What is the rate for the second order reaction A - Products when...
Table 3: Experimental Data for Part 2: Determination of Activation Energy k Time* T* [1] [S,0,?] Rate (M/s) (s) (C) (M) (M) Run 3 153 20.5 .0208 .0416 4.03*10^-6 4.65*10^-3 (Room T) Run 6 198 9 .0208 .0416 3.15*10^-6 3.64*10^-3 (Cool) Run 7 112 31 .0208 .0416 5.58*10^-6 6.45*10^-3 (Warm) Run 8 40 51 .0208 .0416 1.56*10^-5 1.80*10^-2 (Warmer) 1/T (1/K) In k Run 3 1/293.5 -5.37 Run 6 1/282 -5.62 Run 7 1/304 -5.044 Run 8 1/324 -4.02 20....
using the pics of data i provided can someone please help find
the rate law of the reaction and the activatuon energy with
catalyst and without catalyst
Kinetics of the lodine "Clock" Reaction Purpose: Investigate the kinettes reaction of iodide and peoky disulfate, in order to determine the rate law and the Ea with and without a catalyst. deep color Clear builds up because of storch 2 I rag) 5208 cag) → Encaq) + 2 sou? 2- + iaal rate=K[IJh...
ln(k) = -E_a/R 1/T + ln(A) A plot of ln (k)versus 1/T result in a straight line with a slope = -E_a/R. The value of E_a can then be calculated using the value of R and to the slope of the line. This experiment uses the Arrhenius equation, which relates the temperature and specific reaction rate constant to determine the activation energy for the crystal violet reaction. The reaction will be performed at different temperatures. Once the order of reaction...
A plot of In P vs. 1/T yields a straight line of slope -2760 K for a substance. What is AHvap of the substance? A. 37.2 kJ/mol C. 18.7 kJ/mol B. 212 kJ/mol D. 22.9 kJ/mol
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