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2- Below figure is Atwood Machine. How long does it take to the m, to hit...
4. A simple Atwood machine consists of two masses m1 and m2 that are connected by...
4. A simple Atwood machine consists of two masses
m1 and m2 that are
connected by a string wound over a pulley, as seen in the figure
below. Assume m2 is larger than
m1. Motion in the upward direction is positive.
On a piece of paper, draw two free body diagrams; one for each of
the masses, showing all forces acting on each mass. Then answer the
following questions.
Suppose that m2 starts from rest at a height
of 7...
In the Atwood machine shown in (Figure 1) , the pulley radius is 0.10 m ,...
In the Atwood machine shown in (Figure 1) , the pulley radius is
0.10 m , and the rotational inertia of the pulley is 0.17 kg?m2 .
Ignore the cord's inertia.
A)Calculate the acceleration of the
blocks.
B)Calculate the tension in the cord on the left
C)Calculate the tension in the
cord on the right.
In the Atwood machine shown in Figure 5.14a, m1 = 2.00 kg and m2 = 8.00 kg
In the Atwood machine shown in Figure 5.14a, m1 = 2.00 kg and m2 = 8.00 kg. The masses of the pulley and string are negligible by comparison. The pulley turns withoutfriction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.00 m/s downward.Figure 5.14a(a) How far will m1 descend below its initial level?_______m(b) Find the velocity of m1 after 1.80 s._______m/s
In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.00 kg. The...
In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.00 kg. The masses of the pulley and string are negligible by comparison. The pulley turns without friction and the string does not stretch. The lighter object is released with a sharp push that sets it into motion at vi = 2.20 m/s downward. (a) How far will m1 descend below its initial level? 1 m In the Atwood machine shown below, m1 = 2.00 kg and...
4. [14pts total] In class we solved a variation on the Atwood machine to find the...
4. [14pts total] In class we solved a variation on the Atwood machine to find the mag- nitude of the acceleration of the masses, a, and the tension in the string connecting them, T. Now consider this arrangement: e me 02 / Figure 1 If we had solved the case shown in Figure 1, where the surfaces are frictionless and the pulley is massless and frictionless, we would have found: (_ (m2 sin 02 – mj sin 01)g (mi +...
tion 15 of 17 > Attempt 2 < Feedback An Atwood machine consists of two masses...
tion 15 of 17 > Attempt 2 < Feedback An Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pulley are massless and that there is no friction in the pulley. If the masses have the values m = 18.7 kg and m2 = 13.7 kg, find the magnitude of their acceleration a and the tension in the rope. Use g -9.81 m/s Newton's second law...
How 1.63 (c) How long does the ball take to hit the ground after it reaches...
How 1.63 (c) How long does the ball take to hit the ground after it reaches its highest point? 1.63 (d) What is its velocity when it returns to the level from which it started? (Assume the positive direction is upward. Indicate the direction with the sign of your answer) 16 m/s Need Help? Rasd t i-2 points SerCP10 2 P 047 (a) Find the velocity of the object when it is 20.0 m above the ground. (Indicate the direction...
In the atwood machine shown below l, m1= 2.00 kg and m2= 7.70 kg. the masses...
In
the atwood machine shown below l, m1= 2.00 kg and m2= 7.70 kg. the
masses of the pulley and string are negligible by comparison. The
pulley turns without friction and the string does not stretch. The
lighter object is released with a sharp push that sets it into
motion at v -initial= 2.60 m/s downward.
Figure and question are in diagram ( picture below)
In the AtwOOdl motion at n = 2.60 m/s downward. mi 2 (a) How far...
Page 5 Atwood's Machine Problem 2: Setup an Atwood machine using a pulley, string and two...
Page 5 Atwood's Machine Problem 2: Setup an Atwood machine using a pulley, string and two masses. Measure the acceleration of the masses when released from rest and compare to the theoretical value as calculated in Lesson notes. By measuring the elapsed time, and the vertical displacement Ay, the acceleration y, t ep is determined usingAact Compare the measured and theoretical values of a using the percent error formula (see Lesson 6 for aeory). y2 t Table 1: Experimental Data...
please do part B! Part 2: Problems Problem 1:12 points An Atwood machine is made of...
please do part B!
Part 2: Problems Problem 1:12 points An Atwood machine is made of two masses m! = 0 15 kg and m2 = 0 1 kg attached to lightweight (i.e. massless) string placed over a pulley. As always the string does not stretch. The pulley is made of a disk of mass M-0.5 kg and radius R = 0.1 m. The two masses are initially at rest at the same height yinitial-0.75 m above the ground. Use...
4. A simple Atwood machine consists of two masses
m1 and m2 that are
connected by a string wound over a pulley, as seen in the figure
below. Assume m2 is larger than
m1. Motion in the upward direction is positive.
On a piece of paper, draw two free body diagrams; one for each of
the masses, showing all forces acting on each mass. Then answer the
following questions.
Suppose that m2 starts from rest at a height
of 7...
In the Atwood machine shown in (Figure 1) , the pulley radius is
0.10 m , and the rotational inertia of the pulley is 0.17 kg?m2 .
Ignore the cord's inertia.
A)Calculate the acceleration of the
blocks.
B)Calculate the tension in the cord on the left
C)Calculate the tension in the
cord on the right.
4. [14pts total] In class we solved a variation on the Atwood machine to find the mag- nitude of the acceleration of the masses, a, and the tension in the string connecting them, T. Now consider this arrangement: e me 02 / Figure 1 If we had solved the case shown in Figure 1, where the surfaces are frictionless and the pulley is massless and frictionless, we would have found: (_ (m2 sin 02 – mj sin 01)g (mi +...
tion 15 of 17 > Attempt 2 < Feedback An Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pulley are massless and that there is no friction in the pulley. If the masses have the values m = 18.7 kg and m2 = 13.7 kg, find the magnitude of their acceleration a and the tension in the rope. Use g -9.81 m/s Newton's second law...
How 1.63 (c) How long does the ball take to hit the ground after it reaches its highest point? 1.63 (d) What is its velocity when it returns to the level from which it started? (Assume the positive direction is upward. Indicate the direction with the sign of your answer) 16 m/s Need Help? Rasd t i-2 points SerCP10 2 P 047 (a) Find the velocity of the object when it is 20.0 m above the ground. (Indicate the direction...
In
the atwood machine shown below l, m1= 2.00 kg and m2= 7.70 kg. the
masses of the pulley and string are negligible by comparison. The
pulley turns without friction and the string does not stretch. The
lighter object is released with a sharp push that sets it into
motion at v -initial= 2.60 m/s downward.
Figure and question are in diagram ( picture below)
In the AtwOOdl motion at n = 2.60 m/s downward. mi 2 (a) How far...
Page 5 Atwood's Machine Problem 2: Setup an Atwood machine using a pulley, string and two masses. Measure the acceleration of the masses when released from rest and compare to the theoretical value as calculated in Lesson notes. By measuring the elapsed time, and the vertical displacement Ay, the acceleration y, t ep is determined usingAact Compare the measured and theoretical values of a using the percent error formula (see Lesson 6 for aeory). y2 t Table 1: Experimental Data...
please do part B!
Part 2: Problems Problem 1:12 points An Atwood machine is made of two masses m! = 0 15 kg and m2 = 0 1 kg attached to lightweight (i.e. massless) string placed over a pulley. As always the string does not stretch. The pulley is made of a disk of mass M-0.5 kg and radius R = 0.1 m. The two masses are initially at rest at the same height yinitial-0.75 m above the ground. Use...
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