B] acceleration a = 1m/s^2 as found in A part,.
using second equation of motion, s= 0.5at^2 = 0.5*1*1^2 = 0.5 m
So m1 being heavier will come 0.5 m down from initial location, m2 will go up
y1 = 0.75 - 0.5 = 0.25 m
y2 = 0.75 + 0.5 = 1.25 m
a option is correct.
please do part B! Part 2: Problems Problem 1:12 points An Atwood machine is made of...
The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley Assume that the rope and pulley are massless, and that there is no friction in the pulley. If the masses have the values m 19.7 kg and m2 12.7 kg, find the magnitude of their acceleration a and the tension T in the rope. Use g 9.81 m/s2. Number a- m/s Number
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tion 15 of 17 > Attempt 2 < Feedback An Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pulley are massless and that there is no friction in the pulley. If the masses have the values m = 18.7 kg and m2 = 13.7 kg, find the magnitude of their acceleration a and the tension in the rope. Use g -9.81 m/s Newton's second law...
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