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Part 2: Problems Problem 1:12 points An Atwood machine is made of two masses m! = 0 15 kg and m2 = 0 1 kg attached to lightweight (i.e. massless) string placed over a pulley. As always the string does not stretch. The pulley is made of a disk of mass M-0.5 kg and radius R = 0.1 m. The two masses are initially at rest at the same height yinitial-0.75 m above the ground. Use 10 m/s2 for this problem A. Calculate the acceleration of the two masses once they are free to move a. 0.25 m/s b. 0.5 m/s2 d. 2.0 m/s2 B. One second after the motion begins what are the heights yi and y2 of the two masses above the gro a. yi-0.25 m and Y2 1.25 m . 21.5nm c. y,-1.0 m and Y2 = 0.5 m d. = 1.5 m and y2-0.25 m2

please do part B!

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Answer #1

B] acceleration a = 1m/s^2 as found in A part,.

using second equation of motion, s= 0.5at^2 = 0.5*1*1^2 = 0.5 m

So m1 being heavier will come 0.5 m down from initial location, m2 will go up

y1 = 0.75 - 0.5 = 0.25 m

y2 = 0.75 + 0.5 = 1.25 m

a option is correct.

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