FBD of m2
m2 a = m2 g - T
T = m2 g - m2 a... (i)
FBD of m1
m1 a = T - m1 g sin x - u mg cos x
from (i)
m1 a = m2 g - m2 a - m1 g sin x - u m1 g cos x
1.5 * 2.94 = 9.8 m - 2.94 m - 1.5* 9. 8* sin 40 - 0.4* 1.5* 9.8* cos 30
m = 2.763 kg
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Comment in case any doubt, will reply for sure.. Goodluck
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