A) A vacuum-based parallel plate capacitor is connected to a 5.5 V power supply. The plates...
A) A vacuum-based parallel plate capacitor is connected to a 5.5 V power supply. The plates have an area of 2 mm22 and are 5 mm apart. What is the capacitance of the capacitor?
Correct answer: 3.54E-09 uF
B) What is the charge of the positive end of the capacitor?
Correct answer: 1.95E-08 uC
C) Suppose that the capacitor is disconnected from the power supply and the plate separation is increased to 7 mm. How much energy must be used to increase the plate separation ?(Assume no loss of energy to heat or any other such complication.)
A and B are corrected answer. I need help on C please!!! C is not = 2.2*10^-8 uJ (wrong answer)
Homework Answers
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A) A vacuum-based parallel plate capacitor is connected to a 5.5
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A parallel-plate capacitor has capacitance 7.50 uF. (a) How much energy is stored in the capacitor...
A parallel-plate capacitor has capacitance 7.50 uF. (a) How much energy is stored in the capacitor if it is connected to a 19.00-V battery? ա․ (b) If the battery is disconnected and the distance between the charged plates doubled, what is the energy stored? uJ (c) The battery is subsequently reattached to the capacitor, but the plate separation remains as in part (b). How much energy is stored? u]
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A parallel-plate capacitor has capacitance 7.50 uF. (a) How much energy is stored in the capacitor if it is connected to a 19.00-V battery? ա․ (b) If the battery is disconnected and the distance between the charged plates doubled, what is the energy stored? uJ (c) The battery is subsequently reattached to the capacitor, but the plate separation remains as in part (b). How much energy is stored? u]
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