Question

28. The work done by an ideal gas in an isothermal expansion from v volume Vs to volume V, is glven by the formula: w = nRT In(V/V) spheric pressure (1 atm) is 101.3 KPa. If 1.0 L of He gas at room temperature 0 atm of (208C) and 1. work is done on the gas? pressure is compressed isothermally to a volume of 100 mL, how much 02 E 23x1 D) 2.3 x 10 A) 5.6 ku B) 4.7 x10J c) 4.7 x 10 k

Answer 1

We know that the formula gas equation PV = nRT nRT = PV nRT = 101.3 times 10^3 times 1.0 times 10^-3 nRT = 101.3 (1) The given formula is work done by the gas w = nRT ln (v_2/v_1) = 101.3 ln (100/1000) [Therefore from eq no (1) nRT = 101.3 & v_1 = 1.02 = 1000 mL v_2 = 100 mL] = 101.3 times ln (0.1) = 101.3 times -2.3026 = -233.252 J (or) = -2.3 times 10^2 kJ work is done on the gas = -work done by the gas = -(-2.3 times 10^2) kJ = 2.3 times 10^2 kJ Therefore Answer is [D] = 2.3 times 10^2 kJ