Question

5. Find the center of mass of the rectangular lamina with vertices (0.0), (21.0). (0.12), and (21. 12) for the density p = kx

please answer 5-7 in detail

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Answer #1

Consider a small mass element dlm = pdndy at position vechey P = nity f. So that Rome R dm Sentyf) (Sandy) (dm Is fondy Bem =so that = 230.5k / = 29055R(11°/02) = 220.5kľ (12)}- 0 ) = 197000 ; In Pandy at ff py andy g Dem. = (22.22 Gurji + (1970086)

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