Question

Needed in a basic java format. no switch cases please. thanks!!!

(4 pts) Problem 1 An ordinal number can be thought of as the "adjective forin" of a ununber. Examples of ordinal numbers are 1st, 78th, and 782nd. Iu Euglislh, au ordinal nunber can usually be produced by adding "tli" to the end of the number, but there are exceptions for numbers ending in 1 (1st. 101st). 2 (2nd, 892nd). or 3 (3rd, 4573rd). There's also an cxccption to that exception for nunbers that cnd iu 11. 12. or 13 these just use the staudard tlh" (111th. 8013th). (Isu't natural lauguage wonderful??) Within your Lab6HW folder, crcate a new class named OrdinalNumbers.java. Within that class. writc a metliod named toOrdinal that takes one int parameter and returus the ordinal version of that parameter as a string. If the parameter is negative, toordinal should return the string "invalid", toordinal should work correctly for auy non-ncgative int valuc. Here are some example arguments for the toordinal method and their expected return values. Note that the double quotes in the return valucs simply indicate that these arc strings the double quotcs theinselves should not be included as characters within the strings. Argument | Return Włuc 76"invalid" "Oth" 612th" 9922nd" 9922 2147483643 "2147483643rd"

Answer 1

import java.util.List;
import java.util.NoSuchElementException;


class OrdinalNumbers {

    public String toOrdinal(int x) {
        if (x < 0) {
            return "invalid";
        }
        String pref[] = {"th", "st", "nd", "rd", "th", "th", "th", "th", "th", "th"};
        if (x >= 10 && x <= 20) {
            return x + pref[0];
        }
        return x + pref[x % 10];
    }

    public void toOrdinal(int left, int right) {
        for (int i = left; i <= right; i++) {
            System.out.println(toOrdinal(i));
        }
    }

}

class Main {
    public static void main(String[] args) {
        OrdinalNumbers o = new OrdinalNumbers();
        o.toOrdinal(16,28);
    }
}

OUTPUT :

Run Main "C:\Program Files\Java\jdk1.8.0-131\bin\java " 16th 17th 18th 19th to E 20th 22nd 23rd 24th 25th oit 27th 28th Process finished with exit code 0