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Question 7 An online tutoring service claims that students who take their ACT preparation course have a mean ACT score of at

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Answer #1

H0: \mu >= 25.8 ,

Ha: \mu < 25.8

Test statistics

t = ( \bar{x} - \mu ) / ( S / sqrt( n) )

= ( 24.9 - 25.8) / ( 3.8 / sqrt(32 ) )

= -1.34

df = n - 1 = 32 - 1 = 31

From T table,

With test statistics of 1.34 and df of 31,

p-value = 0.0950

Since p-value < 0.10 level, reject H0.

p= 0.0950

We reject the null hypothesis. There is sufficient evidence at 10% level of significance to suggest that

The mean ACT score for the people using his service is less than 25.8

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