The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h (209 km/h) in 2007.
If her racket pushed on the ball for a distance of 0.11 m, what was the average acceleration of the ball during her serve?
Here ,
speed of shot , u = 130 mi/hr
u = 209 km/hr = 209 * 1000/3600 m/s
u = 58.1 m/s
distance , d = 0.11 m
let the average acceleration is a
Using third equation of motion
v^2 - u^2 = 2 * a * d
58.1^2 = 2 * a * 0.11
a = 15343.7 m/s^2
the acceleration of the ball is 15343.7 m/s^2
b)
let the time interval is t
Using second equation of motion
s = u * t + 0.5 * a * t^2
0.11 = 0.5 * 15343.7 * t^2
t = 3.78 *10^-3 s
the time interval of the contact is 3.78 *10^-3 s
The fast server in women's tennis is Venus Williams, who recorded a serve of 130 mi/h...