Problem 115: Determine the molecule of C7H12O
The IR, mass spec, CNMR and HNMR needs to be typed out not handwritten, and the molecule needs to be a digital
representation as well. A base example is provided below:
________________________________________________________________________________________________________
Find and draw the molecule based on these charts (Drawing needs to be digital and please type out answer)
Use an analysis of each graph and explain what numbers indicate what groups.
Base Example
IR:
3500: O-H group
1750: Ester
Mass Spec:
91:
135:
CNMR:
HNMR:
7.5: Aromatic ring
__________________________________________________________________________
Homework Answers
Add Answer to:
Problem 115: Determine the molecule of
C7H12O
The IR, mass spec, CNMR and HNMR needs to...
Find the compounds using NMR and IR: Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000...
Find the compounds using NMR and IR:
Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000 v (cm) 800 3000 1200 4000 100 Mass Spectrum 73 140 138 80 No significant UV 60 115 absorption above 220 nm 40 M 194/196 (1% ) 20 CeH1102Br 120 160 200 240 280 40 80 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH, Cн, сн! solvent proton decoupled 8 (ppm) 160 120 40 200 80 H NMR Spectrum (200 MHz, CDCI,...
Find the compounds using IR and NMR: Problem 25 2251 IR Spectrum (liquid film) 800 1600...
Find the compounds using IR and NMR:
Problem 25 2251 IR Spectrum (liquid film) 800 1600 1200 4000 3000 2000 v (cm) 100 Mass Spectrum M 117 80 77 60 91 40 20 CgH7N 200 80 120 160 240 280 40 m/e expansion 13C NMR Spectrum (100.0 MHz, CDCI, solution) 130 129 ppm DEPT CH Cн,! сн! expansion 130 129 ppm solvent proton decoupled (ppm) 40 200 160 120 80 H NMR Spectrum (400 MHz. CDCI, solution) TMS 10 7...
do the spec problem Problem 9 IR Spectrum (kuid im) 0.0 800 1600 1200 2000 V (cm) 3000 4000 Mass Spectrum 0.5F 100 8...
do the spec problem
Problem 9 IR Spectrum (kuid im) 0.0 800 1600 1200 2000 V (cm) 3000 4000 Mass Spectrum 0.5F 100 80 60 UV spectrum 1,0 77 107 5.815 mg/ 10 mls path length: 1.00 cm solvent: ethanel M 122 20E 1.5 300 350 250 200 200 280 240 120 160 40 80 (nm) m/e 13C NMR Spectrum Aath (20.0 MHz, CDCI, solution) expansion x5 off-resonance decoupled proton decoupled 200 160 120 80 8 (ppm) 40 0 1H...
Please help identify the organic compound using mass spec, ir spec, CNMR, and HNMR. From looking...
Please help identify the
organic compound using mass spec, ir spec, CNMR, and HNMR.
From looking at the mass spec, I believe the molar mass of the
uknown organic compound to be 122 g/mol
From looking at CNMR, I believe there are at least 5 carbons for
each of the 5 peaks. I recall from class that there can be more due
to symmetry, but am not certain how to tell.
Above are all of the graphs given to me...
Formula: C3H7Br Mass Spectrum % of base peak M+ 122/124 IR Spectrum (liquid film) 40 80...
Formula: C3H7Br Mass Spectrum % of base peak M+ 122/124 IR Spectrum (liquid film) 40 80 200 240 280 120 160 m/e 4000 3000 1200 800 2000 V (cm 1600 ) TT 13C NMR Spectrum (50.0 MHz, CDCI, solution) solvent 200 160 120 80 40 0 S (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) 6H, d expansions 4.6 ' 4.0 ppm 2: 0 1 4 ppm 1H, m _ TMS 10 9 8 7 6 5 4 3 2...
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO...
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO 280 40 80 120 160 200 240 13C NMR Spectrum M CDO, Rewives DEPT CHẢ CHỊ CHẾ expansion is higher ed proton decoupled 200 160 120 06 (ppm) "H NMR Spectrum (200 MHz, CDCI, solution) expansion 10 9 8 7 2 1 8 (ppm)
Fall 2019 Problem 3 IR Spectrum (CHC solution) 1350 1170 4000 3000 800 2000 v (cm)...
Fall 2019 Problem 3 IR Spectrum (CHC solution) 1350 1170 4000 3000 800 2000 v (cm) 1600 1200 100 Mass Spectrum 91 80 M 200 60 155 40 172 20 Cg H1203S 240 280 200 120 m/e 160 80 40 13C NMR Spectrum (20.0 MHz, CDCI, solution) C-H C-H H-GH -CH -CH solvent TMS proton decoupled 0 8(ppm) 40 80 120 160 200 H NMR Spectrum (100 MHz. CDCI, solution) TMS 1 8 (ppm) 6 7 8 yeed % of...
Attached are four spectra for isomer with the MF= c12h14o4. Determine the structure for each molecule...
Attached are four spectra for isomer with the MF=
c12h14o4. Determine the structure for each molecule and draw them
below.
problem 63 IR Spectrum (CCI, solution) 1765 4000 3000 1200 800 2000 V (cm ) Mass Spectrum UV Spectrum & 8 8 g 8 of base 2 mar 269 nm (10910€ 2.7) humax 263 nm (10910 2.7) M -222 (< 1) 169 sahent: methanol 8 C12H1404 240 280 40 80 120 160 200 13C NMR Spectrum (50.0 MHz, COCI, solution)...
Find the structure IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0...
Find the structure
IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0 Mass Spectrum 0.5t of base peak UV spectrum 1.075 mg/10ms path length: 0.10 cm solvent: ethanol CH100 280 1.5 40 80 120 160 m/e 200 240 200 250 cm 300 13C NMR Spectrum (1250 MHZ COCI, solution) DEPT CH CH CH! proton decoupled 200160120 80 40 08 (ppm) TH NMR Spectrum (600 MHz, CDCI, solution) expansions expansion pom 10 9 8 7 6 5...
Fall 2019 Problem 5 IR Spectrum (iquid fim) 1715 4000 3000 2000 V (cm) 1600 1200...
Fall 2019 Problem 5 IR Spectrum (iquid fim) 1715 4000 3000 2000 V (cm) 1600 1200 800 100 44 Mass Spectrum 80 60 58 20 M. 86 C5H100 280 40 240 80 200 120 160 13C NMR Spectrum (20.0 MHz, CDCI, solution) -CH3 C-H proton decoupled TMS CH solvent ul 5 (ppm) 40 80 120 160 200 H NMR Spectrum (100 MHz, CDC, solution) expansion of 400 MHz spectrum 20 Hz TMS 0.99 ppm 2.21 2.31 9.75 2 3 6...
Find the compounds using NMR and IR:
Problem 85 IR Spectrum (liquid fiim) 1720 1600 2000 v (cm) 800 3000 1200 4000 100 Mass Spectrum 73 140 138 80 No significant UV 60 115 absorption above 220 nm 40 M 194/196 (1% ) 20 CeH1102Br 120 160 200 240 280 40 80 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH, Cн, сн! solvent proton decoupled 8 (ppm) 160 120 40 200 80 H NMR Spectrum (200 MHz, CDCI,...
Find the compounds using IR and NMR:
Problem 25 2251 IR Spectrum (liquid film) 800 1600 1200 4000 3000 2000 v (cm) 100 Mass Spectrum M 117 80 77 60 91 40 20 CgH7N 200 80 120 160 240 280 40 m/e expansion 13C NMR Spectrum (100.0 MHz, CDCI, solution) 130 129 ppm DEPT CH Cн,! сн! expansion 130 129 ppm solvent proton decoupled (ppm) 40 200 160 120 80 H NMR Spectrum (400 MHz. CDCI, solution) TMS 10 7...
do the spec problem
Problem 9 IR Spectrum (kuid im) 0.0 800 1600 1200 2000 V (cm) 3000 4000 Mass Spectrum 0.5F 100 80 60 UV spectrum 1,0 77 107 5.815 mg/ 10 mls path length: 1.00 cm solvent: ethanel M 122 20E 1.5 300 350 250 200 200 280 240 120 160 40 80 (nm) m/e 13C NMR Spectrum Aath (20.0 MHz, CDCI, solution) expansion x5 off-resonance decoupled proton decoupled 200 160 120 80 8 (ppm) 40 0 1H...
Please help identify the
organic compound using mass spec, ir spec, CNMR, and HNMR.
From looking at the mass spec, I believe the molar mass of the
uknown organic compound to be 122 g/mol
From looking at CNMR, I believe there are at least 5 carbons for
each of the 5 peaks. I recall from class that there can be more due
to symmetry, but am not certain how to tell.
Above are all of the graphs given to me...
Formula: C3H7Br Mass Spectrum % of base peak M+ 122/124 IR Spectrum (liquid film) 40 80 200 240 280 120 160 m/e 4000 3000 1200 800 2000 V (cm 1600 ) TT 13C NMR Spectrum (50.0 MHz, CDCI, solution) solvent 200 160 120 80 40 0 S (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) 6H, d expansions 4.6 ' 4.0 ppm 2: 0 1 4 ppm 1H, m _ TMS 10 9 8 7 6 5 4 3 2...
Problem 4 IR Spectrum ud 1600 LL 4000 2000 1600 1200 800 Mass Spectrum 131 عقل مقلمتململمعلم So base peske 103 M CHO 280 40 80 120 160 200 240 13C NMR Spectrum M CDO, Rewives DEPT CHẢ CHỊ CHẾ expansion is higher ed proton decoupled 200 160 120 06 (ppm) "H NMR Spectrum (200 MHz, CDCI, solution) expansion 10 9 8 7 2 1 8 (ppm)
Fall 2019 Problem 3 IR Spectrum (CHC solution) 1350 1170 4000 3000 800 2000 v (cm) 1600 1200 100 Mass Spectrum 91 80 M 200 60 155 40 172 20 Cg H1203S 240 280 200 120 m/e 160 80 40 13C NMR Spectrum (20.0 MHz, CDCI, solution) C-H C-H H-GH -CH -CH solvent TMS proton decoupled 0 8(ppm) 40 80 120 160 200 H NMR Spectrum (100 MHz. CDCI, solution) TMS 1 8 (ppm) 6 7 8 yeed % of...
Attached are four spectra for isomer with the MF=
c12h14o4. Determine the structure for each molecule and draw them
below.
problem 63 IR Spectrum (CCI, solution) 1765 4000 3000 1200 800 2000 V (cm ) Mass Spectrum UV Spectrum & 8 8 g 8 of base 2 mar 269 nm (10910€ 2.7) humax 263 nm (10910 2.7) M -222 (< 1) 169 sahent: methanol 8 C12H1404 240 280 40 80 120 160 200 13C NMR Spectrum (50.0 MHz, COCI, solution)...
Find the structure
IR Spectrum quid 4000 3000 2000 V (cm 1600 ) 1200 800 0.0 Mass Spectrum 0.5t of base peak UV spectrum 1.075 mg/10ms path length: 0.10 cm solvent: ethanol CH100 280 1.5 40 80 120 160 m/e 200 240 200 250 cm 300 13C NMR Spectrum (1250 MHZ COCI, solution) DEPT CH CH CH! proton decoupled 200160120 80 40 08 (ppm) TH NMR Spectrum (600 MHz, CDCI, solution) expansions expansion pom 10 9 8 7 6 5...
Fall 2019 Problem 5 IR Spectrum (iquid fim) 1715 4000 3000 2000 V (cm) 1600 1200 800 100 44 Mass Spectrum 80 60 58 20 M. 86 C5H100 280 40 240 80 200 120 160 13C NMR Spectrum (20.0 MHz, CDCI, solution) -CH3 C-H proton decoupled TMS CH solvent ul 5 (ppm) 40 80 120 160 200 H NMR Spectrum (100 MHz, CDC, solution) expansion of 400 MHz spectrum 20 Hz TMS 0.99 ppm 2.21 2.31 9.75 2 3 6...
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