Question

1.At standard temperature and a pressure of 619 kPa, a sample of Cl2 gas has a volume of 31.2 liters. How many grams of gas are in the sample?​ ____g 1.

2.Find the volume of 6.50 mol of an ideal gas at 24.0°C and a pressure of 419 kPa. Use the ideal gas law and R = 0.0821 atm • L/mol • K. _______________L

Answer 1

IDEAL GAS EQUA TIOV: A gas which follows these lawS such as Boyles law , Charle's lau . Avogadro's Law'5 is Known as i deal 'The ldeal gas equation is an ejuation that equates the Product of the Pre s54e and thevolume of the one mole of a 9 as to the pvoduct os 'tstemperature and exact fov 41 gas Constant. The e?uations ideal9as eal gas equat/on is used to calculate eithethe Pressuve, volume, 6 o number of moles of 4 gas. P= pre s suve of a gas V volume of a jai Wumbe of moles of a sas T Absolute temperature of a Jas R - Ideal gas Constant R= 0.0821 L. atm mol.k

Calculating Numbeo Moles: . Mole:s is defined as the ya tid of the mass to the molar mass mass (m) Moles (n)? Molar mass (M) . Mass in Sram lor) Kilogvam Molar Hass in gram/mole or) kilosram/mo le 'Mass ỉs defined as the number of moles of the substance multiplied by the molar mass the substance Mass Cm) F moles (n) x Molar Mass (iM) Molar Mass is defined as the ratio of the the substante the mo les o mass (m) mo les (n) mass of the Subs tance to Molav Mass (M)

5 o lution auestion: 1: Ca lculate Mass of a gas RT 丁 2731 R 0.0820s L atm mol k v:31.2L 1 a. atm 6.1091 atn 619 ל 1o1.325 gPa 3.2 6. 104 1 ayin CL1 mol. 90. 6039 mol 2 2. 402 4 CL2-70.906 og/mo) Molar Mass of 8.5082/, x 70.9060%, 603-282g mass of CL2 = 603.282

QueStion:2: Ca lc u lale vo lume: PV= nRT n RT 247 T= 24.0 C +273 し.atm R: o.OS206 419 к% x 1 atm 297 4.135 2 a 584 1683 L 4.1352 38. 31 L . '. volume 38. 31 IL