4. Find the equation of the tangent line to the implicit curve x? - y +...
(1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3+xy=302xy3+xy=30 at the point (10,1)(10,1). (1 point) Use implicit differentiation to find an equation of the tangent line to the curve 2xy3 + xy = 30 at the point (10, 1). The equation -3/70 defines the tangent line to the curve at the point (10, 1).
Find the equation of the tangent line to the curve at the given point using implicit differentiation. Remember: equation of a line can be found by y-y1=m(x-x1) where m is the slope of the line and (x1,y1) is any point on the line. Curve: at (1,1)
Find an equation for the line tangent to the curve at the point defined by the given value of t. x = sin t, y = 2 sin t, t = wa y = 2x - 213 y = 2x y = 2x + 13 Oy=-2x+ 2/3 Find an equation for the line tangent to the curve at the point defined by the given value of t. x=t, y= V2t, t = 18 y=- X-3 y=+x+3 O y = 1...
Find an equation of the tangent line to the curve at the given point. y = x4 + 5x2 - x, (1,5) y = Show My Work (Requiredi 2
13) Find an equation of the tangent line to the curve y=sin(5x)+cos(8x) at the point (π/6,y(π/6)). what is the tangent line: 14) f(x)=4x^2cos(4x) what is the first and second derivatives and solve both for F(5) NOTE There should be four answers! 16) Suppose that f(x)=3x/(4−5x^)3 find an equation for the tangent line to the graph of f at x=2. the tangent line: y=
1. Find an equation of the tangent line to the curve at the given point. x = ++ +1, y=+*+t at the point (2,-2). 2. Find y" by implicit differentiation. (note that a is a constant) x² + y² = a² 3. A piece of wire 12 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total...
Use implicit differentiation to find the slope of the tangent line to the curve 5x^3 y^2 - 4x^2 y = 1at the point (1,1) m=
show all work Find an equation of the tangent line to the curve at the given point/value. x = 2 cos 3t - 4 sin 3t, y = 3 tan 6t; t = 2
please Show clear work and step-by-step instructionsFind the slope and equation of line tangent to the curve y = (2x-16)/√x at x = 4.
Find the equation of tangent line to the curve y = x2 – \sqrt[3]{x} at the point (-1,0).