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The magnetic field perpendicular to a 100 turn coi
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Answer #1

\left |e \right |=\left |-\frac{\mathrm{d} \Phi }{\mathrm{d} t} \right |=N\frac{\mathrm{d} B}{\mathrm{d} t}S

S=area

Num: 0.5 V

Answer (a).

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