here time between two text messages follow exponential distribution
a)P(no text message in two minutes) =P(X>2)=e-x =e-3*2 =0.0025
b)P(2nd text more than 2 minutes after first)=no text message in two minutes) =P(X>2)=e-x =e-3*2 =0.0025
c)P(4th arrive within 30 second(0.5 min) of 3rd)=P(T<0.5)=1-e-3*0.5 =0.7769
8. Your friend sends you text messages at an average rate of 3 per mimite; the...
Messages arrive to a computer server according to a Poisson distribution with a mean rate of 10messages per hour. a) What is the probability that hte first message arrives in the first 5 minutes? (randome variable time) b) What is the probability that 3 messages arrive in 20 minutes? (random variable # of messages)
4 (5 points) The average number of text messages is arrived at a rate of 2 messages per mmute. The probability that, in a 5-minute period, at most one message arrives can be compuled as e 10100 e 10101 e-22 2 C. -200 e 221 a. b. 0! 1!
It has been reported that the average adult sends and receives 658 text messages per week. Imagine that we take a random sample of size n = 250 adults from this population and find that the sample standard deviation is 128.5. We know the sampling distribution of the sample mean in this case would have a standard deviation equal to approximately A 15.81. B 128.5. C 1.51. D 8.13. E 658.
Messages arive to a computer server according to a Poisson distribution with a mean value 12 per hour. Ten of them are I page long, and two are more than 1. OMessages arrive to a computer server according to a Poisson distribution with a What is the probability that 5 short messages are received in 2 hour? b) What is the probability that at least 4 long messages are received in 3hours? 2p c)Determine the length of an interval such...
1. Suppose you get on average 60 text messages per day between 8am and 8pm. Compute the probability that in a particular hour between 8am and 8pm, you will get exactly 10 text messages. Give your answer to five decimal places with a leading zero. Note: ON AVERAGE you get 60 text messages between 8am and 8pm...on average, how many text messages would you expect in one hour?? 2. Suppose you get on average 60 text messages per day between 8am...
A shop has an average of five customers per hour 5. A shop has an average of five customers per hour (a) Assume that the time T between any two customers' arrivals is an exponential random variable. (b) Assume that the number of customers who arrive during a given time period is Poisson. What (c) Let Y, be exponential random variables modeling the time between the ith and i+1st c What is the probability that no customer arrives in the...
Emails arrive at an average rate of 9 per hour. A. What is the probability that more than 5 emails arrive over the next hour? B. What is the probability that the next email arrives within 5 minutes?
a) 3. [10 Points] A student usually receives ten text messages within the lunch hour in a weekday. Consider a 30 minutes' period in a week day lunch. What the probability that he receives no more than 5 messages during that time period? b) What is the probability that he receives more than 5 and less than 15 messages during that time? c) What is the probability that he receives at least 8 test messages during that time period? d)...
Question 3 The number of messages in certain corporate mailbox follows a Poisson distribution with a mean rate of 4 per minute. What is the probability that more than 9 messages are received in that mailbox in 2 minutes? Round your answers to at least two decimals.
how do you find P(S)?? collection of real SMS text messages from partici- pating cellphone users.13 In this collection, 747 of the 5574 total messages (13.40%) are identified as spam. 11.60 The word "free" is contained in 4.75% of all messages, and 3.57% of all messages both contain the word "free" and are marked as spam. (a) What is the probability that a message contains the word "free", given that it is spam? (b) What is the probability that a...