Question

12 points Save Answer Two point charges 91 and 92 are placed at points (0,4.1m) and (5.5m,0), respectively as shown in the figure. 91=13 nC, 92 = -16nC. Take k = 1/(41TE0 ) = 9x109 Nm2/C2 What is the y-component of the electric field vector at the origin due to the charges 91 and 92? Use SI units and provide your answer with two decimal place. 92 (0,0)

Answer 1

The direction of field vactor at origin due to charge $\small q_2$ is along +ve x axis. Since $\small q_2$ is -ve charge, it's field is directed radially inwards i.e towarsa the charge. Therefore, y component of field vector at origin due to $\small q_2$ , i.e. in the perperdicular direction of the field, is 0.

The direction of field vactor at origin due to charge $\small q_1$ is along -ve y axis. Since $\small q_1$ is -ve charge, it's field is directed radially outwards i.e away from the charge. Therefore, y component of field vector at origin due to $\small q_1$

4περr2

$\small =\frac{13\: \times 10^{-9}C\times 9\times 10^9\: Nm^2/C^2}{(5.5\: m)^2}$

$\small =3.87\: N$