Question

To understand the role of friction in a state of equilibrium.

A chair weighing 120 NN rests on a level floor that is not frictionless. A man pushes on the chair with a force FFF = 43.0 NN that is directed at an angle of 42.0 ∘∘ with the horizontal.(Figure 1) Assume that the chair is stationary but is on the verge of sliding.

Mastering Engineering Masterin x 0 = |Liga JS (3) + X C To Determine The Center Of C X + & ► e session.masteringengineering.com/myct/itemView?assignmentProblemlD=10987209&offset=prev O E O MAE 241 - 005 - Spring 2020 <Extra Credit for Test 2&amp;3 Pushing a Chair along the Floor 5 of 9 Review Part A - Normal force exerted on the chair by the floor Learning Goal: To understand the role of friction in a state of equilibrium. A chair weighing 120 N rests on a level floor that is not frictionless. A man pushes on the chair with a torce F = 43.0 N that is directed at an angle of 42.0 with the horizontal.(Figure 1) Assume that the chair is stationary but is on the verge of sliding. Using Newton's laws, calculate the magnitude of the normal force that the floor exerts on the chair. Express your answer numerically to three significant figures in newtons. View Available Hint(s) V A vec O ? Submit Figure Part B - Coefficient of static friction between the chair and the floor What is the coefficient of static friction, f. between the floor and the chair? Recall that the chair is on the verge of sliding. Express your answer numerically to three significant figures. View Available Hint(s) 180 AED 1 vec O 2 ? Submit

Answer 1

N 120 N 43N Chard FEN Weight of chorin e 120N (Acting downward) Le Ny Normal force acting upward. F = Frictional force Against the force 2 - t direction = MN For equilibrium Condition, , 120N force o- Nel vertical = N 43 Sin42 +120 N=148.77 N) supward. Este Net Horizontal force o = F=MN - 43 Cos 42 = 10.2147 43 (os 42 148.77 Thank you