What is the internal energy of 2.0 mol of an ideal monatomic gas
at 300 K?
J
U= Cv *n * R * T
Here
U= Internal Energy
Cv = 3/2 for a monoatomic gas
n= 1 mole
R = 8.314 J/(K * Moles)
T=300K
Therefore, U = 3741.3 Joules
U= ?v *n * R * T = 3/2 * 2*8.314*300 = 7482.6
J
Here
U= Internal Energy
?v = 3/2 for a monoatomic gas
n= 2 mole
R = 8.314 J/(K * Moles)
T=300
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