4. When 1-iodo-1-methylcyclohexane is treated with sodium ethoxide, the more highly substituted alkene product predominates. Alternatively,...
When 1-iodo-1-methylcyclohexane is treated with NaOCH2CH3, the more highly substituted alkene product predominates. When KOC(CH3)3 is used instead, the less highly substituted alkene product predominates. Please explain. A) Methylenecyclohexane is more stable than 1-methylcyclohexene B) The bulky iodo group is attacked mor readily by less bulky NaOCH2CH3 C) KOC(CH3)3 attacks the primary hydrogen, but NaOCH2CH3 attacks the secondary hydrogen D) 1-iodo-1-methylcyclohexane exists only in the chair conformation E) None of the above