Question

Problem 12.25 An object whose moment of inertia is 3.50 kg m torque shown in the figure (Figure 1). experiences the Part A What is the object's angular velocity at 3.00 s? Assume it starts from rest. Express your answer with the appropriate units. CAMA OD ? X 10 x Figure < 1 of 1 rad T (Nm) Value You have already submitted this answer. Enter a new answer No credit lost. Try again. Submit Previous Answers Request Answer Provide Feedback 0 i 2 5"8)

Answer 1

Concept - find the angular impulse by finding the area of torque versus time graph. The angular impulse will be equal to change in angular momentum. The initial angular momentum will be zero because the object starts from rest. We use this to find the final angular velocity as shown below***************************************************************************************************
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angular impulse = area under t-t graph = 1 { wm)(15-05) + (2N.m) (25-15) 1s 3 Nims .ms So, 3 Noms = AL 3 = I (Wf-wi) iwi so I = 3-5kg.me => LOG - 0.857 radls