Question

Review | Constants An object's moment of inertia is 1.7 kg. m. Its angular velocity is increasing at the rate of 3.3 rad/s per second Part A What is the net torque on the object? Express your answer in newton-meters. 190 AED ? Nm Submit Request Answer

Answer 1

Given the moment of inertia I of the object is 1.7kgm^2 and its angular velocity is increasing at a rate of 3.3rad/s per second. Therefore,

$\frac{\mathrm{d} \omega}{\mathrm{d} t}=3.3rad/s^{2}=\alpha$

So the angular acceleration $\alpha$ is 3.3 rad/s^2.

So the net torque on the object is,

$\tau=I\alpha=1.7\times 3.3=5.61Nm$

So the net torque acting on the object is 5.61Nm.