An object's moment of inertia is 2.0kg?m2 . Its angular velocity is increasing at the rate of 3.8rad/s per second.
What is the net torque on the object?
we know,
torque= momentInertia*angularacceleration
=> torque= 2.0 x 3.8
=>torque =7.6 N-m
here,
angular acceleration , a = 3.8rad/s^2
then
Torque = I * a = 2 * 3.8 = 7.6 N.m
An object's moment of inertia is 2.0kg?m2 . Its angular velocity is increasing at the rate...
Review | Constants An object's moment of inertia is 1.7 kg. m. Its angular velocity is increasing at the rate of 3.3 rad/s per second Part A What is the net torque on the object? Express your answer in newton-meters. 190 AED ? Nm Submit Request Answer
3. An object has a moment of inertia equal to 6.0 kg.m. If the object's angular velocity increasing at the rate of 2.0 rad/s, what is the net torque acting on the object?
An object's moment of inertia is 1.60 kgm2 . Its angular velocity is increasing at the rate of 4.00 rad/s2 .
If an object has a moment of inertia 21 kg-m2 and rotates with an angular speed of 113 radians/s, what is its rotational kinetic energy? i la- ro
An object whose moment of inertia is 2.5·kg·m2 experiences the torque shown in the figure. What is the object's angular velocity at t = 2.4·s? Assume it starts from rest. 7 (Nm)
In the diagram, disk 1 has a moment of inertia of 3.2 kg · m2 and is rotating in the counterclockwise direction with an angular velocity of 7.3 rad/s about a frictionless rod passing through its center. A second disk rotating clockwise with an angular velocity of 8.9 rad/s falls from above onto disk 1. The two then rotate as one in the clockwise direction with an angular velocity of 1.8 rad/s. Determine the moment of inertia, in kg ·...
(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.400kg⋅m20.400kg⋅m2 (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity decreases to 1.25 rev/s. (c) Suppose instead he keeps his arms in and allows friction of the ice to slow him to 3.00 rev/s. What average torque was exerted...
(a) Calculate the angular momentum of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.300 kg · m2. _____kg · m2/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his moment of inertia if his angular velocity drops to 1.75 rev/s. ______kg · m2 (c) Suppose instead he keeps his arms in and allows friction with the ice to...
Calculate the angular momentum, in kg · m2/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg · m2. (a) Calculate the angular momentum, in kg . m/s, of an ice skater spinning at 6.00 rev/s given his moment of inertia is 0.330 kg . m2. kg. m/s (b) He reduces his rate of spin (his angular velocity) by extending his arms and increasing his moment of inertia. Find the value of his...
Problem#3 (10 points): A flywheel with a mass moment of inertia is 0.72 Kg m2 starts from rest and accelerated at the rate of 3.4 rad/s2 for 40 s. a) Determine the net torque used for the acceleration of the flywheel. b) Determine the angular velocity reached after 15 s and 35 s. c) Determine the acceleration and compare with given acceleration. Then retardation was applied to this flywheel with a rate of 3.8 rad/s2 to decrease the angular velocity...