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answer to 6th question
Since water is lighter than methylenechloride in density water would be on top while methylenechloride below.
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Some useful Information Ca n he found at the end of the exam 1. A student...
With this information what is the PH of the .1 M acetic acid sol and .1...
With this information what is the PH of the .1 M
acetic acid sol and .1 M acetic acid buffer sol? Please help
solutions to observe that buffers resist pH changes. Burette readings should be made to the nearest 0.1 mL (or 0.05 mL if possible), A. Preparation of Acetic Acid-Acetate Buffer Solution An acetate buffer contains the acid-base pair, acetic acid and the acetate ion (typically added as sodium acetate). For acetic acid, pK, = -log (1.8 x 10-)...
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH3COONa) into 100.00 mL...
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH3COONa) into 100.00 mL of a 0.100 M solution of acetic acid. Then 2.00 mL of a 1.00 M solution of hydrochloric acid is added to the acetic acid/sodium acetate buffer solution. The Ka of acetic acid is 1.8 × 10−5. What is the pH of HCl?
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH2COONa) into 100.00 mL...
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH2COONa) into 100.00 mL of a 0.100 M solution of acetic acid. Then 1.80 mL of a 10.00 M solution of hydrochloric acid is added to the acetic acid/sodium acetate buffer solution. The K, of acetic acid is 1.8 x 10-5. What is the pH of the solution after adding HCI? pH
With this information how would I calculate the pH of .01 M Ammonia solution and the...
With this information how would I calculate the pH of
.01 M Ammonia solution and the pH of .01 M Ammonia buffer
solution
I need
Ph of acetic acid! sorry for the wrong wording!
A. Preparation of Acetic Acid-Acetate Buffer Solution An acetate buffer contains the acid-base pair, acetic acid and the acetate fon (typically added as sodium acetate). For acetic acid, pk, = -log (1.8 10 = 4.74. Consider the con ditions that will yield 100 ml of an...
1. A solution has [HC7H5O2] = 0.100 M and [Ca(C7H5O2)2] = 0.200 M. Ka = 6.3...
1. A solution has [HC7H5O2] = 0.100 M and [Ca(C7H5O2)2] = 0.200 M. Ka = 6.3 × 10-5 for HC7H5O2. The solution volume is 5.00 L. What is the pH of this solution after 5.00 mL 10.0 M HCl is added? 2. Which of the following solution(s) is a buffer? 100 mL of 0.1 M acetic acid mixed with 25 mL of 0.5 M NaOH 50 mL of 0.1 M acetic acid mixed with 25 mL of 0.05 M sodium...
10. Using your answer to 6e: 6e: What percent of the mixture obtained in reaction 1...
10. Using your answer to 6e: 6e: What percent of the
mixture obtained in reaction 1 is the para isomer? para isomer :
37.9%
a) How many millimoles of the para product were
present in the isomeric mixture added in the first step of reaction
2? Please show your work.
b) In order to selectively acetylate the para isomer, equimolar
amounts of acetic anhydride and the para isomer must be present.
Using the millimoles you obtained as your answer to...
Using your answer to 6e: a) How many millimoles of the para product were present in...
Using your answer to 6e:
a) How many millimoles of the para product were
present in the isomeric mixture added in the first step of reaction
2? Please show your work.
b) In order to selectively acetylate the para isomer, equimolar
amounts of acetic anhydride and the para isomer must be present.
Using the millimoles you obtained as your answer to
a), calculate the amount of in milligrams (mg) of
acetic anhydride that should be added in step 2 of...
Calculations The following calculations are necessary to complete your Report Sheet. Consult the table on page...
Calculations The following calculations are necessary to complete your Report Sheet. Consult the table on page 119 for appropriate K and K, values. Complete these calculations on your Report Sheet for complete credit. I. pH of Strong and Weak Acids 1. Calculate the pH of a 0.10 M hydrochloric acid solution, HCl(aq). 2. Calculate the pH of a solution prepared by diluting 5.00 mL of 0.10 M hydrochloric acid, HCl (aq), in enough water to make a 50.0 mL solution....
When setting up the reflux condenser, does it matter if the water flows into the bottom...
When setting up the reflux condenser, does it matter if the
water flows into the bottom or the top of the condenser? If so,
does it have to flow into the bottom or the top, and why? If not,
why does it not matter?
Reaction 2: Reduction NO2 NH4HCO2 NH2 + NO2 Pd/C NO2 NH2 NH2 m-methylaniline p-methylaniline 0-methylaniline ortho meta para Procedure for Reaction 2: 1) The mixture of ortho, meta, and para isomers obtained from reaction 1 (2.4...
Using your answer to question 10 part a, calculate the theoretical amount (in mg) that was...
Using your answer to question 10 part a, calculate the
theoretical amount (in mg) that was expected for the
p-methyl acetanilide product. Be sure to show your
work.
10a: 37.9 x 17.5 / 100 = 6.6325mmol
Reaction 2: Reduction NO2 NH4HCO2 NH2 + NO2 Pd/C NO2 NH2 NH2 m-methylaniline p-methylaniline 0-methylaniline ortho meta para Procedure for Reaction 2: 1) The mixture of ortho, meta, and para isomers obtained from reaction 1 (2.4 g, 17.5 mmoles) was added to a 50...
With this information what is the PH of the .1 M
acetic acid sol and .1 M acetic acid buffer sol? Please help
solutions to observe that buffers resist pH changes. Burette readings should be made to the nearest 0.1 mL (or 0.05 mL if possible), A. Preparation of Acetic Acid-Acetate Buffer Solution An acetate buffer contains the acid-base pair, acetic acid and the acetate ion (typically added as sodium acetate). For acetic acid, pK, = -log (1.8 x 10-)...
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH2COONa) into 100.00 mL of a 0.100 M solution of acetic acid. Then 1.80 mL of a 10.00 M solution of hydrochloric acid is added to the acetic acid/sodium acetate buffer solution. The K, of acetic acid is 1.8 x 10-5. What is the pH of the solution after adding HCI? pH
With this information how would I calculate the pH of
.01 M Ammonia solution and the pH of .01 M Ammonia buffer
solution
I need
Ph of acetic acid! sorry for the wrong wording!
A. Preparation of Acetic Acid-Acetate Buffer Solution An acetate buffer contains the acid-base pair, acetic acid and the acetate fon (typically added as sodium acetate). For acetic acid, pk, = -log (1.8 10 = 4.74. Consider the con ditions that will yield 100 ml of an...
10. Using your answer to 6e: 6e: What percent of the
mixture obtained in reaction 1 is the para isomer? para isomer :
37.9%
a) How many millimoles of the para product were
present in the isomeric mixture added in the first step of reaction
2? Please show your work.
b) In order to selectively acetylate the para isomer, equimolar
amounts of acetic anhydride and the para isomer must be present.
Using the millimoles you obtained as your answer to...
Using your answer to 6e:
a) How many millimoles of the para product were
present in the isomeric mixture added in the first step of reaction
2? Please show your work.
b) In order to selectively acetylate the para isomer, equimolar
amounts of acetic anhydride and the para isomer must be present.
Using the millimoles you obtained as your answer to
a), calculate the amount of in milligrams (mg) of
acetic anhydride that should be added in step 2 of...
Calculations The following calculations are necessary to complete your Report Sheet. Consult the table on page 119 for appropriate K and K, values. Complete these calculations on your Report Sheet for complete credit. I. pH of Strong and Weak Acids 1. Calculate the pH of a 0.10 M hydrochloric acid solution, HCl(aq). 2. Calculate the pH of a solution prepared by diluting 5.00 mL of 0.10 M hydrochloric acid, HCl (aq), in enough water to make a 50.0 mL solution....
When setting up the reflux condenser, does it matter if the
water flows into the bottom or the top of the condenser? If so,
does it have to flow into the bottom or the top, and why? If not,
why does it not matter?
Reaction 2: Reduction NO2 NH4HCO2 NH2 + NO2 Pd/C NO2 NH2 NH2 m-methylaniline p-methylaniline 0-methylaniline ortho meta para Procedure for Reaction 2: 1) The mixture of ortho, meta, and para isomers obtained from reaction 1 (2.4...
Using your answer to question 10 part a, calculate the
theoretical amount (in mg) that was expected for the
p-methyl acetanilide product. Be sure to show your
work.
10a: 37.9 x 17.5 / 100 = 6.6325mmol
Reaction 2: Reduction NO2 NH4HCO2 NH2 + NO2 Pd/C NO2 NH2 NH2 m-methylaniline p-methylaniline 0-methylaniline ortho meta para Procedure for Reaction 2: 1) The mixture of ortho, meta, and para isomers obtained from reaction 1 (2.4 g, 17.5 mmoles) was added to a 50...
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