Question

Instructions In c++ write a program that reads in a string of zeros and ones without spaces and for each 8 digits (one byte) outputs the corresponding value in decimal format. The output numbers are separated by spaces. Stop when a character different than 0 or 1 is encountered. The final output may be generated from less than 8 digits but no output should be generated for the final character. Should work for example: input: 00000011000000010010X output: 3 1 2

Answer 1

#include <iostream>
using namespace std;

int main()

{
    long bin, dec = 0, rem, num, base = 1;
    cout << "Enter the binary number(1s and 0s) : ";

int i=1;
int a=0;        // this variable is used to form number

char num2;      // to input char from user

cin >> num2;

while(i<=7&&(num2=='1' ||num2=='0' ))
{
    a=a*10+num2-48;
    cin >> num2;
    i++;
}

num=a;

    bin = num;

    while (num > 0)

    {

        rem = num % 10;

        dec = dec + rem * base;

        base = base * 2;

        num = num / 10;

    }

cout << "\nThe decimal equivalent of " << bin << " : ";

int save[8];
int j=0;

while(dec>0)
    {

    save[j]=dec%10;
    j++;
    dec=dec/10;
    //cout<<dec;

    }

for(int i=j-1;i>=0;i--)
{
cout<<save[i]<<" ";
}
    return 0;

}

Output

"FAc plus try.exe" 1010101w nter the binary number 1s and 0s The decimal equivalent of 1010101 85 Process returned 0 〈0x0〉 execution time : 192.682 s Press any key to continue.