Question

The molarity of a silver nitrate solution is 0.192 M. How many grams of silver ions are present in 53.7 mL?

Answer 1

molarity = moles / volume in liters

here molarity = 0.192 M

volume = 0.0537 L

moles = molrity * volume

moles = 0.192 * 0.0537 => 0.0103104 moles

siver nitrate has the following formula AgNO3

1 mol AgNO3 contains the 1 mole of Ag+ ions

1mol AgNO3 -------------------> 1 mol Ag+

0.0103104 mol --------------------->?

=> 0.0103104 moles

mass of Ag+ => 0.0103104 mol * 107.8682 g/mol => 1.112164 g

answer => 1.112 grams