Ans 7 :
Let the mass of solution be 100 mL
so amount of silver nitrate in solution = (15 x 100 ) / 100 = 15 g
Mol silver nitrate = mass / molar mass
= 15 g / 169.78 g/mol
= 0.088 mol
Molarity = mol solute / volume solution (L)
= 0.088 mol / 0.100 L
= 0.88 M
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