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How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution?

How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution? The molar mass of silver nitrate is 169.9 g/mol. One approach is to solve the molarity relationship (M- n/N) for moles. o a 19.6g b. 6.82 g O5.10 g o d. 1.95 g O e. None of the above
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Concentration of AgNO, 0.15M mol = 0.15 Volume of AgNO,-770.0 mL × 1000mL 0.7700 mol Number of moles of AgNo-0.15x0.7700L 0.1

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