You have 5 ul of a pure (undiluted) culture at a concentration of 3.6 x 106...

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You have 5 ul of a pure (undiluted) culture at a concentration of 3.6 x 106...

You have 5 ul of a pure (undiluted) culture at a concentration of 3.6 x 106 cells/ml. You then add 495 ul sterile diluent. What is the dilution factor ? What is the final concentration (following the dilution) ? NOTE: Use the formula V1 x D1 = V2 x D2 to solve this problem.

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Answer 1

Answer #1

DF = 495 + 5 / 5 = 500/5 = 100

Dilution = 1/100 = 0.01

Final concentration = 3.6 × 10^6 / 100 = 3.6 × 10^4 CFU per ml

Or

V1D1 = V2D2

(3.6 × 10^6)(5) = D2(500)

D2 = 3.6 × 10^4 CFU per ml

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Answer 2

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