Question

You have a stock solution that contains 24 mg/ml of protein. You want to make a set of standards with the following concentrations: 12 mg/ml, 6 mg/ml, 3 mg/ml and 1.5 mg/ml.              

You need a minimum of 500 ul of each standard after all dilutions are completed.

Using the technique of serial dilution, explain how you would make your standards by filling in the chart below.

	Std 1	Std 2	Std 3	Std 4
concentration (mg/ml)	12	6	3	1.5
dilution factor/ from ?
volume of concentrate
volume of diluent
final dilution of stock
final volume/tube

You have a stock solution that contains 2 mg/ml of protein. You want to make a set of standards with the following concentrations: 150 mg/ml, 50 mg/ml, 16.67 mg/ml, and

5.56 mg/ml.

You need a minimum of 300 ul of each standard.

Using the technique of serial dilution, explain how you would make your standards by filling in the chart below.

	Std 1	Std 2	Std 3	Std 4
concentration
dilution factor / from ?
volume of concentrate
volume of diluent
final dilution of stock
final volume/tube

Dilute the following making sure you end up with a minimum volume of at least 10 ml.

stock conc	desired conc	dilution factor	volume stock	volume diluent
20 mg/ml	5 mg/ml
15 mg/ml	2 mg/ml
500 mg/ml	0.5 mg/ml
1000 mg/ml	25 mg/ml
7 mg/ml	0.1 mg/ml
30 mg/ml	1.5 mg/ml
20% (v/v)	0.05% (v/v)
10x	0.1x
50x	1x
125% (w/v)	5% (w/v)
106 cells/ml	2x104 cells/ml
20 ppm	1 ppm
3% (w/v)	2% (w/v)
100% (v/v)	7.5% (v/v)

Please answer all parts thank you.

Answer 1

Stock	desired	factor	Vol stock	vol dilutent (ml)
20mg/ml	5mg/ml	4	2.5ml	7.5
15 mg/ml	2 mg/ml	7.5	1.33ml	8.67
500 mg/ml	0.5 mg/ml	1000	10ul	9ml 990 ul
1000 mg/ml	25 mg/ml	1000/25= 40	250ul	9ml 750ul
7 mg/ml	0.1 mg/ml	70	143ul	9ml 857ul
10x	0.1x	100	100ul	9ml 900ul
100% (v/v)	7.5%	13.33	750ul	9ml 250ul

The 1st part is shown in the following image-

HUUUJIZUIL The Stock = 24 mg/ml for 500ml - 12 mg/n :- 24 xxz 12x500 x 250 ml 2 times Vol. of diluent 250ml. I sell:- 24x2 2 6x500 x 125ml Vol. of diluentz 375ml ] 6mg 4 times 3 mgstal: 28x1 2 3x500 2 z 62.5 8 times vol. of diluent = 437.51 w = 62.5 8 times 16 times. - 240 x = 1.5x500 xz 31.25 diluent2 468.75 I