1. Dilution factor:
To get the D.F., you divide the final volume by the initial volume.
Explanation: D.F.=Vf/Vi
a= 240/36= 6.67
b=c=d=e= 240/120 = 2
2. Molecular weight of CuSO4= 159.61 g/mol
1 ppm = 1 mg in in 1000 mL
800 ppm = 800 mg in 1000 mL
= 0.8 g in 1000 mL
=(0.8/159.61) moles in 1000 mL
= 0.0050 moles in 1000 mL
Now, molarity= number of moles in 1000 mL
Here, molarity= 0.0050 M
800 ppm= 800 mg/ Litre
=(800 x 1000 ) μg/ Litre
= 8 x105 μg/ Litre
Amount in μg/ Litre is known as ppb.
So,ppb= 8 x105
Now, 1 ppb= 1000 ppt
ppb means μg/ Litre and ppt means ng/Litre
1 μg= 1000 ng (nanogram)
So, ppt= 8 x105 x 1000
= 8 x 108
III. The equation needed to solve this question is as follows
For T1, 36 x 800 = 360 x C2
or, C2= 80 ppm
For T2, 120 x 80 = 360 x C3
or, C3= 26.67 ppm
For T3, 120 x 26.67 = 360 x C4
or, C4= 8.89 ppm
For T4, 120 x 8.89 = 360 x C5
or, C5= 2.96 ppm
For T5, 129 x 2.96 = 360 x C6
or, C6= 0.99 ppm
IV. 100 x 0.99 = 500 x B1
or, B1= 0.2 ppm
1 ppm= 1mg/Litre
0.2 ppm = 0.2 mg/ Litre
= 0.0002 g/ Litre
=(0.0002/ 159.61) moles/ Litre
= 1.23 x 10-3 moles/Litre
so, molarity= 1.23 x 10-3 M
=1.238 x 10-3 x 106 μM
= 1238 μM
1) Figure below show a 36 uL of stock solution containing 800 ppm of CuSO4 was...
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