Assuming that a chemical reaction doubles in rate for each 10 degree C temperature increase, by...

Question

Question

Answer 1

Answer #1

given

for every 10⁰c temperature increase, the rate of reaction doubles.

i.e., rate_(t+10)0c / rate_t0c = 2

For exapme consider the temperature change from 0⁰c to 40⁰c

rate_10⁰c / rate_0⁰c = 2

rate_20⁰c / rate_10⁰c = 2

rate_30⁰c / rate_20⁰c = 2

rate_40⁰c / rate_30⁰c= 2

therefore,

rate_40⁰c / rate_0⁰c = (rate_10⁰c / rate0⁰c) * (rate_20⁰c / rate_10⁰c ) * (rate_30⁰c / rate_20⁰c ) * (rate_40⁰c / rate_30⁰c)

= 2 * 2* 2* 2

= 16

Answer 2

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