Question

Shown at the right is a three-dimensional unit cell pattern for a structure of packed spheres. The center of each of eight spheres is at a corner of the cube, and the part of each that lies within the boundaries of the cube is shown. If all of the sphere segments enclosed inside the unit cell boundaries could be glued together, how many whole spheres could be constructed? Which ion of each pair is larger? Hint: How do the sizes of cations and anions compare to the size of the neutral atom they came from? What are the trends in size of atoms in the periodic table? Circle your choice. A. Na or CI B. Zn2 or S

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1) there are eight corners in cube.

each sphere contribute 1/8 th of sphere.

number of sphere in unit cell = 8 * 1 / 8 = 1 (answer).

2)

In the periodic table, from left to right size of the element decreases due to increasing the effective nucler charge.

from top to bottom, size of the element decreases.

with increasing the positive charge on element, size decreses. so size of the neutral atom is greater than cation.

when one or more electron take in valence orbital then element covert to anion. size increases due to electron electron repulsion.

cosidering this,

A) Cl- ion have larger size.

B) S^2- have larger size.

Add a comment
Know the answer?
Add Answer to:
Shown at the right is a three-dimensional unit cell pattern for a structure of packed spheres....
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Answer question 23-25 The unit cell for HCP is not a cube. This structure is made...

    Answer question 23-25 The unit cell for HCP is not a cube. This structure is made by placing one flat layer of a close packed hexagon arrangement of seven spheres on top of the holes in another layer, a third layer directly above first layer, and so on. This layering is referred to as A,B,A,B. Hold the model up to the light and note the tunnels that pass straight through the structure. See the figure below. 23. What is the...

  • Question 5 of 16 ) Attempt 1 Consider the body-centered cubic unit cell shown in this...

    Question 5 of 16 ) Attempt 1 Consider the body-centered cubic unit cell shown in this image. How many corner atoms are shown in the image? number of corner atoms: 8 How many body atoms are shown in the image? number of body atoms: Each body atom is fully inside the boundaries of the cube. What fraction of each corner atom is inside the boundaries of the cube? How many body atoms are shown in the image? number of body...

  • The atoms of crystalline solid pack together into a three-dimensional array of many small repeating units...

    The atoms of crystalline solid pack together into a three-dimensional array of many small repeating units called unit cells. The simplest of the unit cells are those that have cubic symmetry, with atoms positioned at the corners of a cube. Atoms can also be found in the sides (faces) of the cube, or centered within the body of the cube. It is important to realize that a unit cell is surrounded by other unit cells in every direction. Therefore, face...

  • Q. 3. Potassium fluoride adopts the rock salt (NaCl type) structure, with a density of 2.48...

    Q. 3. Potassium fluoride adopts the rock salt (NaCl type) structure, with a density of 2.48 g/cm3. Using the data for the Part 4 model you constructed, calculate the expected distance between the center of the potassium ion and the center of an adjacent fluoride ion in pm. Q. 4. The diameter of a Cs+ ion is 334 pm; the diameter of a Br- ion is 392 pm. For CsBr, which crystallizes in the CsCl type structure from Part 5,...

  • Unit Cell Calculations Name _____________________________ Unit Cells: The Simplest Repeating Unit in a Crystal The structure...

    Unit Cell Calculations Name _____________________________ Unit Cells: The Simplest Repeating Unit in a Crystal The structure of solids can be described as if they were three-dimensional analogs of a piece of wallpaper. Wallpaper has a regular repeating design that extends from one edge to the other. Crystals have a similar repeating design, but in this case the design extends in three dimensions from one edge of the solid to the other. We can unambiguously describe a piece of wallpaper by...

  • Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra...

    Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...

  • 5. What was the purpose of the NaNO3 solution in this experiment? 6. Could a solution...

    5. What was the purpose of the NaNO3 solution in this experiment? 6. Could a solution of NaCl be used instead of NaNO3? 7. What was the purpose of FeSO4 solution in this experiment? 8. Could a solution of FeCl, be used instead of FeSO4? 9. Could a solution of NaSO4 be used instead of FeSO4? 10. Calculate the standard cell potential for the spontaneous redox reaction between a Pb(s)/Pb(NO3)2(aq) half-cell and a Ag(s)/AgNO3(aq) half-cell. Which metal would be oxidized?...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT