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A study of Pennsylvania hospitals showed that the mean patient length of stay in 2001 was...
2. A study of Pennsylvania hospitals showed that the mean patient length of stay in 2001...
2. A study of Pennsylvania hospitals showed that the mean patient length of stay in 2001 was 4.87 days with a standard deviation of 0.97 days. Assume that the distribution of patient length of stay is normally distributed. Sketch an appropriate GRAPH for EACH PART and shade appropriately region. Round to 4 decimal places. (3 points each) a) Find the probability that a randomly selected patient has a length of stay of greater than 7days. b) What is the probability...
The length of maternity stay in U.S. hospitals is normally distributed, with mean of 3.5 days...
The length of maternity stay in U.S. hospitals is normally distributed, with mean of 3.5 days and a standard deviation of 0.5 days. We randomly survey 62 women who recently bore children in U.S. hospitals. Let Xmaternity stay in U.S. hospital, and Xaverage maternity stay for a sample of size 62 a. (30) Xickone) .) b. (.30) X ~ (pick one) . (.40) Which of the following is more likely? Oan individual stays more than 5 days the average stay...
Problem 4 The length of maternity stay in U.S. hospitals is normally distributed, with mean of...
Problem 4 The length of maternity stay in U.S. hospitals is normally distributed, with mean of 2.6 days and a standard deviation of 0.5 days. We randomly survey 89 women who recently bore children in U.S. hospitals. Let X = maternity stay in U.S. hospital, and X = average maternity stay for a sample of size 89 a. X (pick one) ) b. X (pick one) . с. What is the probability that the average stay is more than 3...
Problem 3 The length of matermity stay in US. hospitals is normally distributed. with mean of...
Problem 3 The length of matermity stay in US. hospitals is normally distributed. with mean of 2.5 days and a standard deviation of 1.2 days. survey 68 women who recently bore children in U.S, hospitals Let X maternity stay in U.S. hospital, and X average maternity stay for a sample of size 68 a (30) X pick one) b. (30) x ~ | (pick one" l ( c (40) Which of the following is more likely? O an individual stays...
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community...
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community hospitals in the United States is 6 days Assume that the population standard deviation is 7.7 days. A simple random sample of 49 patients is drawn from this population. 1. What is the sampling distribution of the sample mean? 2. What is the probability that the average length of stay for this group of patients will be no more thana week? 3. What is...
What kind of instruments were used in the study? Did it clearly link to the research...
What kind of instruments were used in the study? Did it
clearly link to the research question? (One paragraph
minimum)
Page Organlzation of Hospital Nursing and 30-day Readmissions In Medicare Patlents Undergoing Surgery Chenjuan Ma, PhD National Database of Nursing Quality Indicators, University of Kansas School of Nursing 3901 Rainbow Bvd, M/S 3060 Kansas City, KS 66160, USA Matthew D McHugh, PhD, and Center for Heath Outcomes and Palcy Research University of Pennsyivania School of Nursing 418 Cune Bivd., Fagin...
Score: 0.33 of 1 pt 13 of 16 (14 complete) 7.2.47 The mean incubation time of...
Score: 0.33 of 1 pt 13 of 16 (14 complete) 7.2.47 The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 da (a) Determine the 14th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. Click the icon to view a table of areas under the normal curve (a) The 14th percentile for incubation times is days. (Round to the...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day (a) Determine the 10th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. = Click the icon to view a table of areas under the normal curve. (a) The 10th percentile for incubation times is days. (Round to the nearest...
pls help me An electrical firm manufactures light bulbs that have a length of life that...
pls help me
An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed with a standard deviation of 35 hours. If a sample of 50 bulbs has an average life of 730 hours, find a 96% confidence interval for the population mean of all bulbs produced by this firm. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table....
please explain 3.3) [8 pts] A sample of 29 randomly selected automobile owners were asked to...
please explain
3.3) [8 pts] A sample of 29 randomly selected automobile owners were asked to keep a record of the kilometers they travel. The random sample showed an average of 28,350 kilometers and a standard deviation of 5,237 kilometers. Assuming the underlying population is normally distributed, test the hypothesis that automobiles are driven on average more than 28,000 kilometers per year at the 10% level. Hou = 28,000 Hu> 28,000 First, specify: "If {inequality} we fail to reject the...
2. A study of Pennsylvania hospitals showed that the mean patient length of stay in 2001 was 4.87 days with a standard deviation of 0.97 days. Assume that the distribution of patient length of stay is normally distributed. Sketch an appropriate GRAPH for EACH PART and shade appropriately region. Round to 4 decimal places. (3 points each) a) Find the probability that a randomly selected patient has a length of stay of greater than 7days. b) What is the probability...
The length of maternity stay in U.S. hospitals is normally distributed, with mean of 3.5 days and a standard deviation of 0.5 days. We randomly survey 62 women who recently bore children in U.S. hospitals. Let Xmaternity stay in U.S. hospital, and Xaverage maternity stay for a sample of size 62 a. (30) Xickone) .) b. (.30) X ~ (pick one) . (.40) Which of the following is more likely? Oan individual stays more than 5 days the average stay...
Problem 4 The length of maternity stay in U.S. hospitals is normally distributed, with mean of 2.6 days and a standard deviation of 0.5 days. We randomly survey 89 women who recently bore children in U.S. hospitals. Let X = maternity stay in U.S. hospital, and X = average maternity stay for a sample of size 89 a. X (pick one) ) b. X (pick one) . с. What is the probability that the average stay is more than 3...
Problem 3 The length of matermity stay in US. hospitals is normally distributed. with mean of 2.5 days and a standard deviation of 1.2 days. survey 68 women who recently bore children in U.S, hospitals Let X maternity stay in U.S. hospital, and X average maternity stay for a sample of size 68 a (30) X pick one) b. (30) x ~ | (pick one" l ( c (40) Which of the following is more likely? O an individual stays...
Name: Wit: SAMPLING DISTRIBUTION EXERCISE The average length of a hospital stay in general or community hospitals in the United States is 6 days Assume that the population standard deviation is 7.7 days. A simple random sample of 49 patients is drawn from this population. 1. What is the sampling distribution of the sample mean? 2. What is the probability that the average length of stay for this group of patients will be no more thana week? 3. What is...
What kind of instruments were used in the study? Did it
clearly link to the research question? (One paragraph
minimum)
Page Organlzation of Hospital Nursing and 30-day Readmissions In Medicare Patlents Undergoing Surgery Chenjuan Ma, PhD National Database of Nursing Quality Indicators, University of Kansas School of Nursing 3901 Rainbow Bvd, M/S 3060 Kansas City, KS 66160, USA Matthew D McHugh, PhD, and Center for Heath Outcomes and Palcy Research University of Pennsyivania School of Nursing 418 Cune Bivd., Fagin...
Score: 0.33 of 1 pt 13 of 16 (14 complete) 7.2.47 The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 da (a) Determine the 14th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. Click the icon to view a table of areas under the normal curve (a) The 14th percentile for incubation times is days. (Round to the...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day (a) Determine the 10th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. = Click the icon to view a table of areas under the normal curve. (a) The 10th percentile for incubation times is days. (Round to the nearest...
pls help me
An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed with a standard deviation of 35 hours. If a sample of 50 bulbs has an average life of 730 hours, find a 96% confidence interval for the population mean of all bulbs produced by this firm. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table....
please explain
3.3) [8 pts] A sample of 29 randomly selected automobile owners were asked to keep a record of the kilometers they travel. The random sample showed an average of 28,350 kilometers and a standard deviation of 5,237 kilometers. Assuming the underlying population is normally distributed, test the hypothesis that automobiles are driven on average more than 28,000 kilometers per year at the 10% level. Hou = 28,000 Hu> 28,000 First, specify: "If {inequality} we fail to reject the...
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