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For the Dissolving of PbCl2 in water Ksp is 1.7 x 10^-5. calculate deltaG standard at 25 degrees C.
12. For the dissolving of PbCl2 in water Ksp is 1.7 x 10-5. Calculate AG at 25°C. If [Pb2+] = .010M and [Cl-) = .01M what is
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Answer #1

Solution : T = 25°C = (25+273.15) K= 298.15K = 298K K. = 1.7x10- PbCl2(S)= Pb2+ (aq) +2a- (aq) K. - [Pb2+ ][-] AG° =-RTINK Su

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