Calculate the solubility of lead chloride,
PbCl2 in units of grams per liter.
Ksp(PbCl2) =
1.7×10-5.
solubility = g/L
Let the solubility of pbcl2 is X M
PbCl2. = Pb2+ + 2cl-
X X. 2X
Ksp = X (2X)2= 4X3
4X3= 1.7 E-5
X3= 1.7/4 E-5
X= 1.619E-2
Solubility in g/L= 0.01619× 278.1= 4.50g/L
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Relorences pt The Kp for lead chloride (PbCl2) is 1.6 x 10-5. Calculate the solubility of lead chloride in each of the following. a. water mol/L Solubility = b. 0,17 M Pb(NO3)2 Solubility = _ c. 0.017 M NaCI Solubility = mol/L Submit Answer Try Another Version 7 ltem attempts remaining
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