Question

Estimate the solubility of lead(II) chloride in grams per liter. Ksp = 1.6x10-5 Submit Show Approach Hide Tutor Steps

Answer 1

Solution :- The value provided in one question are, Ksp of lead (11) chloride = 1.6810², The Reaction is Pbela - P62t + aci 0 + 2x +x The equation of Ksp of p bela is kop = [sear] [cr] Ksp - x x (anja = nx una = 4.33 - 5 1.68 10² = 4 23 1.68105 3 3 . = 4 x 106

a n = 4x100 n=3548186 = 1.5878 102 an M = molarity of lead (11) chloride is 1.5878102 m we have, givemass molar mass. volume of solution in Litre Gram molar mass м - - gram x 1 melasmass

.. molasi ty x molar mass - molar mass of lead (u) chloride = 278.19 mol - molarity x molar mass = 1.587 x 102 x 278.1g. mol - 4.4139/ Hence the solubility of lead (11) chloride in grams per letre is 4.413 9 /