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F (10pts) An object with a mass of 0.25 kg has an initial speed of v=-3 m/s. Two different forces are applied to the mass at

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Answer #1

The acceleration of the object from t=0 to t=3 s

ax=Fx/m =4.0N/0.25 =16m/s^2

Using equation of the motion

v=v_i +a_x t

Here vi= -3m/s , ax =16m/s/s t=3.0s

v=-3+16*3 = 45 m/s

The acceleration of the object from 3s to 5s

ax =Fx/m =-2/0.25 =- 8m/s/s

Using equation of the motion

v_f =v+a_x t

v_f =45-8.0*2

v_f =29 m/s. Answer

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