Question

ignment FULL SCREEN PRINTER VERSION BACK NEXT Chapter 21, Problem 40 GO Chalkboard Video A horizontal wire is hung from the ceiling of a room by two massless strings. The wire has a length of 0.10 m and a mass of 0.005 kg. A uniform magnetic field of magnitude 0.055 T is directed from the ceiling to the floor. When a current of I - 42 A exists in the wire, the wire swings upward and, at equilibrium, makes an angle with respect to the vertical, as the drawing shows. Find (a) the angle and (b) the tension in each of the two strings. ZA = (a) (b) T- Version 4.24.18.1 Pevacy Policy 1 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley Sons Inc Type here to search ' oete * Nê Vije

Answer 1

Solution: Given that: Length of the wire = 0.10 m 1. mars = 0.005 kg Magnitude of uniform Magnetic field - 0.055T current (1) = 424 kle know that: when a Current Carrying wire is placed in a magnetic field, then magnetic force cacting on it is given 1 by F = B1L . = 0.a . (0.055) x(42 ) (0.10) For = 012311 the . 1. To find We know angle tano = F Mg tano - (0.231 N) (0.005 kg) (9.8 m/5) 0.231N tano 0.049

tan0 = 4.71428 0 = tan-'(4.714-38) 0 = 78.02° To find tensi on in each of the two strings strings the tension het 'T' be in each of the then at coso = mg mg T= & cosoli a = (0.005 kg) (9.8 m/s) "a cos (78.02.) TE 0.049 0.41514048 T = 0- 1180 N