x̅ = 66.7, s = 2.1, n = 20
a) Null and Alternative hypothesis:
Ho : µ = 64.9
H1 : µ > 64.9
b) since the sample size is 20, we need to assume that distribution is normal.
c) Test statistic:
t = (x̅- µ)/(s/√n) = (66.7 - 64.9)/(2.1/√20) = 3.8333
df = n-1 = 19
Critical value :
Right tailed critical value, t-crit = ABS(T.INV(0.05, 19)) = 1.729
Reject Ho if t > 1.729
p-value :
Right tailed p-value = T.DIST.RT(3.8333, 19) = 0.0006
Decision:
p-value < α, Reject the null hypothesis
There is enough evidence to conclude that women desire to be taller than they actually are at 0.05 significance level.
For a sample of n = 20 women aged 18 to 29, responses to the question...
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