Question

(1 point) The heights of women aged 20 to 29 follow approximately the N(64, 2.68) distribution. Men the same age have heights distributed as N(69.3 2.69). What percent of young women are taller than the mean height of young men?

Answer 1

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1.

Normal distribution has been given whose params are :

women:

mean = 64,
Stdev = 2.68

men:

mean =69.3
stdev = 2.68

%age of young women are taller than mean height of young men
= P(X>69.3)
= P(Z> (69.3-64)/2.68) = P(Z>1.978) = 1-0.976 = .024 or 2.4%

So, 2.69% of young women are taller than the mean height of young men