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If a small mass starts off with a velocity (v_0) a
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Answer #1

3)


let,

small mass is m

by using conservation of momentum,


m*v0+M*(0)=(m+M)*vf

==> vf=(m/(m+M))*v0

here,

two masses stick to gethere and they travel in the direction of the velocity of vo

4)


length of the pendulum is l=1m

mass m=5kg

maximum speed Vo=3m/sec


===> 1/2*m*v0^2=m*g*h


1/2*vo^2=g*h


1/2*3^2=9.8*h

====> h=0.46 m

maximum height, h=0.46 m

5)


here,


1/2*m*v^2-1/2*m*u^2=m*g*h

1/2*m*v^2-1/2*m*u^2=m*g*l*(1-cos(thet))

v^2-u^2=2*g*l*(1-cos(thet))

here,

h=l-l*cos(theta)

h=l(1-cos(theta))

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