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A soil scientist has just developed a new type of fertilizer and she wants to determine...

A soil scientist has just developed a new type of fertilizer and she wants to determine whether it helps carrots grow larger. She sets up several pots of soil and plants one carrot seed in each pot. Fertilizer is added to half the pots. All the pots are placed in a temperature-controlled greenhouse where they receive adequate light and equal amounts of water. After two months of growth, the scientist harvests the carrots and weighs them (in kilograms). Below is a data table showing the weight of the carrots at the end of the growing period from the two treatment groups.

Sample ID Control Fertilizer Treatment
1 0.358 0.336
2 0.338 0.438
3 0.488 0.458
4 0.374 0.797
5 0.411 0.588
6 0.442 0.326
7 0.376 0.193
8 0.334 0.297
9 0.498 0.486
10 0.403 0.203
11 0.473 0.5
12 0.238 0.214
13 0.298 0.599
14 0.222 0.2
15 0.318 0.598
16 0.337 0.454
17 0.398 0.563
18 0.35 0.692
19 0.285 0.685
20 0.383 0.493
21 0.275 0.361
22 0.332 0.206
23 0.469 0.701
24 0.497 0.255
25 0.352 0.541
26 0.296 0.49
27 0.48 0.257
28 0.266 0.526
29 0.461 0.822
30 0.26 0.63

When analyzing this dataset with a t-test, the  hypothesis states that the average size of the carrots from each treatment are the same, whereas the  hypothesis states that the fertilized carrots are larger in size.

To analyze this data set, the scientist should use a -tailed t-test.

After performing a t-test assuming equal variances using the data analysis add-in for MS Excel, what is the calculated t-value for this data set?

Round your answer to four decimal places.

Your answer should be a positive value.

Report the appropriate critical t value, based on your decision of a one- or two-tailed test, calculated by MS Excel using the Data Analysis add-in.

Round your answer to four decimal places.

What is the appropriate p value for the t-test?

Report your answer in exponential notation

Report your answer to 4 decimal places after converting to exponential notation

e.g.

1.1234E-01 for 0.112341

3.1234E-04 for 0.000312341

Would you reject or fail to reject the null hypothesis?

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Answer #1

we can answer this in excel by going to data > data analysis tab and selecting the t test

Please note that this is a right tail t test as we are interested in the "larger" part of the test

? Tell me what you want to Flash -B Rem Advanced Columns Es Data File Home Insert Page Layout Formulas Data Show Queries Ll Connections A ZA Clear From Table Properties Get ExternaNew Refresh Text to Data Que Recent SourcesksAL Sotitr Recent Sources All cesEdit Links Sort Fiter Reapply Get & Transform Connections Sort & Filter E7 1 Control Fertilizer Treatment 23 2-1 0.358 3 0.338 4 0.488 5 0.374 6 0.411 7 0.442 0.376 9 0.334 10 0.498 11 0.403 12 0.473 30.238 0.298 0.336 Data Analysis 0.438 Analysis Tools 0.458 0.797Random Number Generation 0.588 0.326Sampling 0.193 0.297 0.486 0.203 OK Histogram Moving Average Cancel Rank and Percentile Regression Help t-Test: Paired Two Sample for Means t-Test: Two-Sample Assuming Equal Variances t-Test: Two-Sample Assuming Unequal Variances z-Test: Two Sample for Means 0.5 0.214 0.599

we see that the p value of the test is 0.0005 for 1 tail , which is less than 0.05 , hence we reject the null hypothesis in favor of alternate hypothesis .

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