Energy is required to break the bonds and energy is released when the new bonds are formed . The net sum of these bond energies is called as enthalpy change of the reaction .
For the first reaction :
The bonds to be broken are :
N triple bond N ( B.E. = 941 KJ/mol)
O=O ( B.E. = 495 KJ/mol)
New bonds formed =
two N= O ( B.E. = 607 KJ/mol)
Delta H = 941 + 495 + (2 x -607)
= 222 KJ/mol
For the second reaction :
Bonds broken are :
two C=O = 799 KJ/mol
Bonds formed are :
two CO bonds = 1077 KJ / mol
And since the heat of sublimation is +719 KJ /mol
the delta H = 719 + (2 x 799) + (2 x -1077)
= 163 KJ/mol
Use the average bond energies in the text to estimate the enthalpy changes of the following...
.127. Use average bond energies to estimate the enthalpy changes of the following reactions: N2(g)+3 H2(g)2 NH(g) b. N2(g)+2 H2(g)H,NNH2(g) c. 2 N(g) + O(g)2 N,O(g) a. 9.103. Consider the following molecular ions: N2, O2, C2, and Br22. Using MO theory, (a) write their orbital electron configuration; (b) predict their bond orders; (c) state whether you expect any of these species to exist.
05 Question (2points) e See page 404 Use the average bond energies in the text to estimate the enthalpy changes of the following reactions. 2nd attempt Part 1 (1 point) See Periodíc Table See Hint N, (g) + O2 (g) ? 2NO (g) 229 kJ/mol Part 2 (1 point) C(s) + CO2(g) ? 2CO(g) Note: The heat of sublimation of graphite, C(s), is 719 kJ/mol. 69
05 Question (2 points) a See page 404 Use the average bond energies in the text to estimate the enthalpy changes of the following reactions. 3rd attempt Part 1 (1 point) Feedback i See Periodic Table See Hint N2(g)+02(g) >2NO(g) kJ/mol Part 2 (1 point) Feedback
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The enthalpy change for the following reaction is -137 kJ....
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