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Please do both 6 & 7 they are together

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10 g of water is melted at it normal melting point

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Answer #1

6.

Amount of Heat flow, q=mcpdT

m is mass, c is specific heat capacity of water which is 1 cal/g, dT is change in temperature

Consider initial temperature to be -10oC i.e. 263 K

Hence, q=10\times1\times(273-263)

q=100 cal

entropy change, \Delta S=q/\Delta T

\Delta S=100/10

\Delta S=10 cal/K

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