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4. A recent survey of 1 047 employees of a certain company found that 28% (.28) of them would fire their bosses if they could. What is the mean and standard deviation of this binomial distribution?
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Fot a bimomial disttibution Hehe n-10++ , b=0.28 293-16 1047 × 0.28x(1-0-28) ニ293-16 × 0.72 = θ 211-0752 Standand deviation V

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