A recent survey of 1044 employees found that 34% of them would lay off their bosses if they could. Complete parts a through d below based on a random sample of 10 employees.
a. What is the probability that exactly three employees would lay off their boss?
The probability is ____
(Round to four decimal places as needed.)
b. What is the probability that three or fewer employees would lay off their bosses?
The probability is ____
(Round to four decimal places as needed.)
C). What is the probability that five or more employees would lay off their bosses?
D) What are the mean and standard deviation for this distribution?
A recent survey of 1044 employees found that 34% of them would lay off their bosses...
A recent survey of 1010 employees found that 25% of them would lay off their bosses if they could. Complete parts a through d below based on a random sample of 10 employees. a. What is the probability that exactly three employees would lay off their boss? The probability is 0.2503 . (Round to four decimal places as needed.) b. What is the probability that three or fewer employees would lay off their bosses? The probability is 0.7759. (Round to...
4. A recent survey of 1 047 employees of a certain company found that 28% (.28) of them would fire their bosses if they could. What is the mean and standard deviation of this binomial distribution?
According to a survey of 25,000 households. 49% of the people watching a special event on TV enoyed the commercials more than the event tsell. Complete parts a through e below based on a random sample of nine people who watched the special event a. What is the probability that exactly three people enjoyed the commercials more than the event? The probability is (Round to four decimal places as needed) b. What is the probability that less than four people...
Having trouble with part C According to a survey in a country. 34% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below Click here to view the standard normal distribution table (Rage 1). Click here to view the standard normal distribution table (page 2). C Approximately normal because n SU.USN and np(1-P)2 TU Determine the mean of the sampling distribution of p. HA = 0.34...
According to a recent survey, the average daily rate for a luxury hotel is $232.84. Assume the daily rate follows a normal probability distribution with a standard deviation of $22.92. Complete parts a through d below. a. What is the probability that a randomly selected luxury hotel's daily rate will be less than $ 245? (Round to four decimal places as needed.) b. What is the probability that a randomly selected luxury hotel's daily rate will be more than $...
According to a survey in a country, 34% of adults do not own a credit card. Suppose a simple random sample of 300 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2) the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the (a) Describe the sampling...
The answers are in red. Please do explain all parts According to a recent survey, the average daily rate for a luxury hotel is $234.19. Assume the daily rate follows a normal probability distribution with a standard deviation of $22.42 Complete parts a through d below a. What is the probability that a randomly selected luxury hotel's daily rate will be less than $248? 0.7310 (Round to four decimal places as needed.) b. What is the probability that a randomly...
According to a recent survey of households, the poll found that 48% of the adults watching a special event on TV enjoyed the commercials more than the event itself. Consider a random sample of nine adults who watched the special event. Complete parts a through d below. 1 (3 pts) What is the probability that less than four people enjoyed the commercials more than the event? what is the probablility that exactly six or seven people enjoyed the commericals more...
8.3.33-T Question Help In a recent survey, 154 of 460 employees responded that they typically took work with them on vacation and 81 responded that there are unwritten and unspoken expectations that they stay connected Complete parts (a) through (c) below a Construct a 95% confidence interval estimate for the population proportion of employees who typically take work with them on vacation. (Round to four decimal places as needed)
Question 3 of 13 (1 point) A survey of 1050 U.S. adults found that 34% of people said that they would get no work done on Cyber Monday since they would spend all day shopping online. Find the 95% confidence interval of the true proportion. Round intermediate answers to at least five decimal places Round your final answers to three places ep