Question

answer both 8&9 pls

Question 8 2 pts What is the equivalent capacitance of this circuit? Give answer in mF. sv I Question 9 5 pts A charge Q - +10C is kept at a distance of 1 cm from a large plate of charge distribution. The total surface charge density that is distributed in the plane is given by = +0.0177 Cm. the mass of the charge is 10 mg, how much time (in milliseconds) will it take the charge to move by 10 cm due to the repulsion from the plate?

Answer 1

Dear Student,

SOV ME 500 MF C3 JE Solution :-(8) i and C2 are in parallel so their equivalent 4,25 G +62 = 500+500 = 1000 MF = Imf L Now, on this Csiz is in series with Ca so, net equivalent smf alt and cu do + È = Ï + ✓ +$ : . CScanned with CamScanner

Q=louc mid Id=iem (9) Giren, Q = some = 10x10° c d=1cm = 10²m. o=0.0177 mcm² mass of charge, m=10mg = 10x10kg.. We know that, Electric field due to infinite charge plate is So, foBD of chang particle qExQ qa ing so, EXQ-mg ama. -g -a) or, 0.0177X16*x10x1050 071 ca or, 0.0177x10x10x106 2x8.85 x1012 x10x1630 10x1539= a Now, So, 1. ", la = -8.81 m/s2 Hence, acceleration is in downward directio. s=10cm= 0.lm. so ut + hat? 0.1=0*t + *8081x+2 to set as - 150.1 ms csscanned with CamScanner

Hope it helps.

Thanks.