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A survey was conducted to determine what percentage of college seniors would have chosen to attend a different college if the

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Answer #1

71. Binomial.

72. Mean, µ = n*p = 12 * 0.34 =    4.08

73. Standard deviation, σ = √(n*p*(1-p)) = √(12 * 0.34 * 0.66) =    1.6410

74. Probability of at least 5, P(X ≥ 5) = 1 - P(X ≤ 4)
Using excel binomial function:     
= 1 - BINOM.DIST(4, 12, 0.34, 1)     
= 0.3876  

75. Probability of exactly 5, P(X = 5) =
= 12!/(5!* 7!) * 0.34^5 * 0.66^7
= 0.1963

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