Question

* Question The experimental data from a certain reaction gives these three graphs. What is the order for this reaction? MA In [A] zero order o first order second order third order o 11 : 4 özés

Answer 1

For the order of reaction is integrated vate equation ni kyma=ht when ere to is Initial concentration of reactant A is concentration of reactant at any time to n is order of reaction, n) 2 ] k is rate Constant This is for first order. We compare the y-axus with TAJ tor Ant as from above rate equation, On comparing [Anth to TA] , we get TAJntl = TAJ -n+1=1 n=0 but we know e know n nto, as this ea to, as this equation is valid for ny,2. and for n=o, z ero order, rate is concentration independent. so it is for n=l, according to TA=TAJ e-kt TAJ varies with negative power of exponential with respect to time, hence satisfy the graph. 2). on comparing IN Sajat [A] = [A]nt 1=nt [1=21 Second order reaction, t - This first order , as A = Ao e-kt Taking log on both sids InA = hAokt (y=mx+c) = JOA